A hummingbird, flapping its wings to stay above a flower. Is an example of which newtons law?

A 10-µf capacitor is plugged into a 110 v-rms 60-hz voltage source. what is the rms value of the current through the capacitor?

ValentinkaMS [17]

The rms value of current is0.414A, and the maximum value of current is 0.585A.

To find the answer, we have to study about the capacitive reactance.

<h3>How to find the rms and maximum value of current?</h3>

We have the expression for rms value of current as,

$I_{rms}=\frac{V_{rms}}{X_c}$

where; Xc is the capacitive reactance of the circuit.

We have the capacitive reactance as,

$X_c=\frac{1}{2\pi fC} =\frac{1}{2\pi *60*10*10^{-6}} =265.39 Ohm$

Thus, the value of rms current will be,

$I_{rms}=\frac{110}{265.39} =0.414A$

Thus, the maximum value of current will be,

$I_0=\sqrt{2}*I_{rms} =0.585A$

Thus, we can conclude that, the rms value of current is0.414A, and the maximum value of current is 0.585A.

Learn more about the capacitive reactance here:

brainly.com/question/27853857

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7 0

2 years ago

A 0.10 kg stone is thrown from the edge of an ocean cliff with an initial speed

AfilCa [17]

Answer:

79.20 joule

Explanation:

1.

A 0.10kg stone is thrown from the edge of an ocean cliff with an initial speed of 21m/s. When it strikes the water below, it is traveling at 45m/s. What is the change in kinetic energy of the stone?

ΔEk = m/2*(V2^2-V1^2) = 0.05*(45^2-21^2) = 79.20 joule

6 0

3 years ago

Which of the following is the highest ranking taxa into which living organisms are classified in Linnaean taxonomy?

Mila [183]

Answer:

Im pretty sure its kingdom

Explanation:

I have a test with the same question and I got it right putting the answer as kingdom.

4 0

3 years ago

A block pushed along the floor with velocity v0xv0x slides a distance dd after the pushing force is removed. If the mass of the

Volgvan

Answer:

There is no change in distance

Explanation:

Given that block slides a distance dd with initial velocity $v_{ox}$ $v_{ox}$

Work energy theorem states that Work done W is the difference between final kinetic energy $KE_{f}$ and initial kinetic energy $KE_{i}$

W = $KE_{f}$ - $KE_{i}$ ...........(equation 1)

In the given problem, the work is done by frictional force

Hence the work done is given by

$W_{Friction}$ = - $F_{Friction}$ x dd

$F_{Friction}$ is negative since it is resistive force and dd is the distance

$W_{Friction}$ = - μ mg X dd

where μ is coefficient of friction.

Also we know that Kinetic energy KE = $\frac{1}{2}$ $mv^{2}$

$KE_{f}$ = 0 since final velocity is zero

$KE_{i}$ = $\frac{1}{2}$ $m(v_{ox} v_{ox}) ^{2}$

Substituting the corresponding values equation 1 becomes

-μ mg x dd = 0 - $\frac{1}{2}$ $m(v_{ox} v_{ox}) ^{2}$

dd= $\frac{(v_{ox}v_{ox} )^{2} }{2g}$ x (1/μ) ........... (equation 2)

To find distance when mass of block is doubled and initial velocity is not changed:

Equation 2 shows that the distance dd is independent of mass, therefore there is no change in distance.

5 0

3 years ago

What is the magnitude of the gravitational force exerted by earth on a 9.0-kg brick when the brick is in free fall?

GarryVolchara [31]

The magnitude is 9.000kg

4 0

3 years ago