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Jet001 [13]
3 years ago
9

Simplify the expression9x⁰y⁸____z⁸

Mathematics
2 answers:
NARA [144]3 years ago
5 0

simplified the answer is:

9y^8/z^8

Olenka [21]3 years ago
3 0

Anything raised to exponent 0 equals 1

So

x^{0}=1

So we get

\frac{9 (1) y^8}{z^8} = \frac{9y^8}{z^8}

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Please Answer ASAP ! Which point lies on the circle represented by the equation x2 + (y − 12)2 = 252?
Ivahew [28]

Answer:

Point (20 , -3) lies on the circle ⇒ (A)

Step-by-step explanation:

The point which lies on the circle must satisfy the equation of the circle

The equation of the circle is x² + (y - 12)² = 25²

<em>Take the left hand side and substitute x and y by the coordinates of each point the answer must equal the right hand side</em>

<em />

A. (20 , -3)

∵ x = 20

∵ y = -3

∴ (20)² + (-3 - 12)² = 400 + (-15)² = 400 + 225 = 625

∵ The right hand side is 25²

∵ 25² = 625

∴ The left hand side = The right hand side

∴ Point (20 , -3) satisfy the equation of the circle

∴ Point (20 , -3) lies on the circle

B. (-7 , 24)

∵ x = -7

∵ y = 24

∴ (-7)² + (24 - 12)² = 49 + (12)² = 49 + 144 = 193

∵ The right hand side is 25² = 625

∴ Point (-7 , 24) does not lie on the circle

C. (0 , 13)

∵ x = 0

∵ y = 13

∴ (0)² + (13 - 12)² = 0 + (1)² = 0 + 1 = 1

∵ The right hand side is 25² = 625

∴ Point (0 , 13) does not lie on the circle

D. (-25 , -13)

∵ x = -25

∵ y = -13

∴ (-25)² + (-13 - 12)² = 625 + (-25)² = 625 + 625 = 1250

∵ The right hand side is 25² = 625

∴ Point (-25 , -13) does not lie on the circle

6 0
3 years ago
300 is 100% of what number?
laiz [17]
300/x=100/100
(300/x)*x=(100/100)*x       - we multiply both sides of the equation by x
300=1*x       - we divide both sides of the equation by (1) to get x
300/1=x 
300=x 
x=300

now we have: 
100% of 300=300

The answer is 300

8 0
3 years ago
(Anderson, 1.14) Assume that P(A) = 0.4 and P(B) = 0.7. Making no further assumptions on A and B, show that P(A ∩ B) satisfies 0
Goshia [24]

Answer with Step-by-step explanation:

We are given that

P(A)=0.4 and P(B)=0.7

We know that

P(A)+P(B)+P(A\cap B)=P(A\cup B)

We know that

Maximum value of P(A\cup B)=1 and minimum value of P(A\cup B)=0

0\leq P(A\cup B )\leq 1

0\leq P(A)+P(B)-P(A\cap B)\leq 1

0\leq 0.4+0.7-P(A\cap B)\leq 1

0\leq 1.1-P(A\cap B)\leq 1

0\leq 1.1-P(A\cap B)

P(A\cap B)\leq 1.1

It is not possible that P(A\cap B) is equal to 1.1

1.1-P(A\cap B)\leq 1

-P(A\cap B)\leq 1-1.1=-0.1

Multiply by (-1) on both sides

P(A\cap B)\geq 0.1

Again, P(A\cup B)\geq P(B)

0.4+0.7-P(A\cap B)\geq 0.7

1.1-P(A\cap B)\geq 0.7

-P(A\cap B)\geq -1.1+0.7=-0.4

Multiply by (-1) on both sides

P(A\cap B)\leq 0.4

Hence, 0.1\leq P(A\cap B)\leq 0.4

3 0
3 years ago
Can some one please help me !!
irina1246 [14]
Should be 55 I believe
3 0
3 years ago
Read 2 more answers
Pls help it’s due today
seraphim [82]

Answer:

ion know

Step-by-step explanation:

3 0
3 years ago
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