harold was 5 years older than Mary. In 10 years he found that 4 times his age exceeded twice Mary's age by only 50. How old were
Harold and Mary in the beginning?
1 answer:
in the beginning
Harold X+5
Mary X
In 10 years
Harold X+5+10 X+15
Mary X+10
4(X+15)-2(X+10)=50
4X+60-2X-20=50
2X+40=50
2X=50-40
2X=10
X= 10÷2
X=5
Harold At The Beginning 5+5=10
Mary At The Beginning 5
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