<h3>Given</h3>
4 hundreds flats; 5 tens rods; 2 ones cubes
<h3>Find</h3>
The number of hundreds flats in each of 2 equal piles
<h3>Solution</h3>
When 4 flats are divided into two equal groups, each group will have ...
... 2 flats
_____
You can imagine doing this the way a card dealer might: first put 1 flat in each of 2 piles, then do the same for the remaining 2 flats. Each pile will end up with 2 flats.
— — — — —
You will have a problem if you continue with the tens rods. There is an odd number of those, so one of them will have to be exchanged for 10 ones cubes.
X+0.5 could be an inequality to represent the possible weight of the second fish, unless you can tell me the weight of the first fish?
Answer:
t = 4
Step-by-step explanation:
Given
+ 3 = 5 ( subtract 3 from both sides )
= 2
Multiply both sides by 2 to clear the fraction
t = 2 × 2 = 4
Answer:
i would say 18/24
Step-by-step explanation:
