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<h2>Nitrogen fixation </h2>
Explanation:
It is the process of converting free nitrogen into nitrogenous compounds .
Let us study about it :
In nature there are certain plants called as leguminous plants .These plants have nitrogen fixing bacteria called as rhizobium in their root nodules .
This bacteria can convert free atmospheric nitrogen into ammonia .
Then this ammonia with the help of bacteria nitrosomonas and nitrobacter gets converted into nitrites and nitrates .
Then these nitrites and nitrates with the help of bacteria like pseudomonas gets converted back into free nitrogen ,
This cycle helps in enriching the soil and to maintain nitrogen percent constant in atmosphere ,
The biogeochemical cycle : for nitrogen is attached below
Answer:
The fraction of the available octahedral positions are filled with ions is
Explanation:
If there are n numbers of spheres in HCP in packing:
Number of octahedral void = n
Number of tetrahedral void = 2n
Total number of voids = n + 2n = 3n
The crystal structure consists of an HCP arrangement of
ions.
Number of spheres in HCP = 6
Number of = 6
Number of octahedral voids = 6
Number of tetrahedral void = 12
Number of aluminum ions when there are 6 ion =
Number of voids in which ions are present = 4
The fraction of the available octahedral positions are filled with ions =
Answer:
9.8 L
Explanation:
The reaction that takes place is:
- 4H₂(g) + CS₂(g) → CH₄(g)+ 2H₂S(g)
At STP, 1 mol of any gas occupies 22.4 L.
We <u>calculate how many moles are there in 2.5 L of CH₄ at STP</u>:
- 2.5 L ÷ 22.4 L/mol = 0.11 mol CH₄
Then we <u>convert CH₄ moles into H₂ moles</u>, using the<em> stoichiometric coefficients of the reaction</em>:
- 0.11 mol CH₄ *
= 0.44 mol H₂
Finally we <u>calculate the volume that 0.44 moles of H₂ would occupy at STP</u>:
- 0.44 mol * 22.4 L/mol = 9.8 L