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3 years ago

A common oxidizing agent is..?

Chemistry

1 answer:

zimovet [89]3 years ago

8 0

Answer:

C. KMnO4/H+

Explanation:

Oxidizing agent is a substance that has the ability to accept electrons from other substances.

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a solid with a low melting point is most likely what? A.ionic B. covalent C. metallic or D. None of the above.

ziro4ka [17]

The correct answer of the given question above would be option D. None of the above. When a solid has a low melting point, it is most likely a simple molecular substance. When it is ionic, covalent or metallic, it is already considered as a solid with a high melting point.

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3 years ago

Which of the following characteristics do all of the outer planets have in common? A. They lack moons. B. They are small and den

Bogdan [553]

I think the correct answer from the choices listed above is option D. Outer planets are mostly made up of gases and are huge in size. These gases are hydrogen and helium. These outer planets are Saturn, Jupiter, Uranus, and Neptune. Hope this answers the question.

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3 years ago

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1.)What is the molarity of a solution that contains 55.0 grams of Na2SO4 in 250 milliliters of solution? (The mass of one mole o

Maurinko [17]

1)1.549=1.55M

2)may include all of these characteristics

3)stronger the acid

4)lower the concentration of H3O+ ions

4 0

3 years ago

Determine the maximum number of moles of product that can be produced from 7.0 mol al and 8.0 mol cl2 according to the equation

Vilka [71]

The balanced chemical reaction is

2al + 3cl2 = 2alcl3

To determine the maximum amount of product, we need to determine which is the limiting reactant. Then, use the initial amount of that reactant to calculate the amount of the product that would be produced. We do as follows:

7 mol Al (3 mol Cl2 / 2 mol Al) = 10.5 mol Cl2
8 mol Cl2 ( 2 mol Al / 3 mol Cl2) = 5.3 mol Al
Thus, it is Cl2 that is the limiting reactant.

8 mol Cl2 ( 2 mol AlCl3 / 3 mol Cl2) = 5.3 moles of AlCl3 is produced

5 0

3 years ago

Determine the mass of Al(C2H3O2)3 that contains 2.63 Χ 1024 atoms of oxygen.

sergejj [24]

The molecular formula of compound is $Al(C_{2}H_{3}O_{2})_{3}$ .

Since, in 1 mole of $Al(C_{2}H_{3}O_{2})_{3}$ there are $6.023\times 10^{23}$ atoms of $Al(C_{2}H_{3}O_{2})_{3}$ .

Thus, according to molecular formula, in 1 mole of $Al(C_{2}H_{3}O_{2})_{3}$ there are $6\times 6.023\times 10^{23}=3.61\times 10^{24}$ atoms of oxygen atoms.

1 atom of oxygen will be present in $\frac{1}{3.61\times 10^{24}}$ moles of $Al(C_{2}H_{3}O_{2})_{3}$ . Thus,

$2.63\times 10^{24} atoms of oxygen \rightarrow \frac{2.63\times 10^{23}}{3.61\times 10^{24}}= 0.7285 moles of Al(C_{2}H_{3}O_{2})_{3}$ .

Molar mass of $Al(C_{2}H_{3}O_{2})_{3}$ is 236 g/mol, mass can be calculated as follows:

$m=n\times M=0.7285 mol\times 236 g/mol=172 g$

Therefore, mass of $Al(C_{2}H_{3}O_{2})_{3}$ will be 172 g.

5 0

3 years ago

Read 2 more answers