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3 years ago

First sign of lung cancer

2 answers:

5 0

the most common first sign of lung cancer is a constant cough. there could also be coughing up blood or reddish colored spit, and chest pain when you laugh, cough, and breathe.

vodka [1.7K]3 years ago

3 0

So, my Nana had lung cancer and she just recently passed away from it because they could not find her a new lungs for a transplant. Signs aren't typically noticeable or seem severe until you get tested and realize you have lung cancer. Some signs would be a new cough that doesn't go away and maybe even have a very heavy chest, shortness of breath, or coughing up blood sputum (spit or phlegm) A lot of the "symptoms" could be similar to a cold or even asthma. I would say if you don't have asthma or asthma history it would be good to go to the doctor to get it checked out. Like I said they are all very similar to a cold or something like that but should be checked out if continuous.

I hope this helps :)

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Why do we use the name electromagnetism to describe the force of an

ElenaW [278]

Answer:

magnet, gravity

Explanation:

5 0

3 years ago

A 3.15-kg object is moving in a plane, with its x and y coordinates given by x = 6t2 − 4 and y = 5t3 + 6, where x and y are in m

ArbitrLikvidat [17]

Answer:

Explanation:

The sum of force along both components x and y is expressed as;

$\sum Fx = ma_x \ and \ \sum Fy = ma_y$

The magnitude of the net force which is also known as the resultant will be expressed as $R =\sqrt{(\sum Fx)^2 + (\sum Fx )^2}$

To get the resultant, we need to get the sum of the forces along each components. But first lets get the acceleration along the components first.

Given the position of the object along the x-component to be x = 6t² − 4;

$a_x = \frac{d^2 x }{dt^2}$

$a_x = \frac{d}{dt}(\frac{dx}{dt} )\\ \\a_x = \frac{d}{dt}(6t^{2}-4 )\\\\a_x = \frac{d}{dt}(12t )\\\\a_x = 12m/s^{2}$

Similarly,

$a_y = \frac{d}{dt}(\frac{dy}{dt} )\\ \\a_y = \frac{d}{dt}(5t^{3} +6 )\\\\a_y = \frac{d}{dt}(15t^{2} )\\\\a_y = 30t\\a_y \ at \ t= 2.15s; a_y = 30(2.15)\\a_y = 64.5m/s^2$

$\sum F_x = 3.15 * 12 = 37.8N\\\sum F_y = 3.15 * 64.5 = 203.18N$

$R = \sqrt{37.8^2+203.18^2}\\ \\R = \sqrt{1428.84+41,282.11}\\ \\R = \sqrt{42.710.95}\\ \\R = 206.67N$

Hence, the magnitude of the net force acting on this object at t = 2.15 s is approximately 206.67N

7 0

3 years ago

Any magnetic properties occur _____________

lyudmila [28]

Answer:

wen you stick to mangnetits togater

Explanation:

7 0

3 years ago

Read 2 more answers

A farmer hitches her tractor to a sled loaded with firewood and pulls it a distance

Delvig [45]

(a) The work done by the force applied by the tractor is 79,968.47 J.

(b) The work done by the frictional force on the tractor is 55,977.93 J.

<h3>Work done by the applied force</h3>

The work done by the force applied by the tractor is calculated as follows;

W = Fd cosθ

W = (5000 x 20) x cos(36.9)

W = 79,968.47 J

<h3>Work done by frictional force</h3>

W = Ffd cosθ

W = (3500 x 20) x cos(36.9)

W = 55,977.93 J

<h3>Net work done by all the forces on the tractor</h3>

W(net) = work done by applied force - work done by friction force

W(net) = 79,968.47 J - 55,977.93 J

W(net) = 23,990.54 J

Learn more about work done here: brainly.com/question/25573309

#SPJ1

4 0

1 year ago

The thermal energy in a heat engine is used to move a piston. Which best describes why this is possible?

mestny [16]

The increase in entropy is directly related to the increase in temperature.

5 0

3 years ago