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3 years ago

The thermal energy in a heat engine is used to move a piston. Which best describes why this is possible?

Physics

1 answer:

mestny [16]3 years ago

5 0

The increase in entropy is directly related to the increase in temperature.

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Pls help on this one?

sattari [20]

The answer is point C

4 0

2 years ago

Submarines need to be extremely strong to withstand the extremely high pressure of water pushing down on them. An experimental r

Brrunno [24]

1500 I think so but I not sure

8 0

2 years ago

List three (3) specific examples of each biological<br> Homeostasis:<br> Metabolism:<br> Growth:

Andre45 [30]

Answer:

Homeostasis: When bacteria or viruses that can make you ill get into your body, your lymphatic system kicks in to help maintain homeostasis.

Metabolism: The processes of making and breaking down glucose molecules are example of metabolism.(respiration and photosynthesis)

Growth:The liver continues to form new cells to replace senescent and dying ones.

Hope these examples help you.

4 0

2 years ago

Which are properties of a liquid? Check all that apply.

Strike441 [17]

Answer:

the property of liquid are

1 they can flow from one place to another if surface is slanted

2 it cannot be compressed

6 0

2 years ago

Consider the hydrogen atom. How does the energy difference between adjacent orbit radii change as the principal quantum number i

Kisachek [45]

Answer:

the energy difference between adjacent levels decreases as the quantum number increases

Explanation:

The energy levels of the hydrogen atom are given by the following formula:

$E=-E_0 \frac{1}{n^2}$

where

$E_0 = 13.6 eV$ is a constant

n is the level number

We can write therefore the energy difference between adjacent levels as

$\Delta E=-13.6 eV (\frac{1}{n^2}-\frac{1}{(n+1)^2})$

We see that this difference decreases as the level number (n) increases. For example, the difference between the levels n=1 and n=2 is

$\Delta E=-13.6 eV(\frac{1}{1^2}-\frac{1}{2^2})=-13.6 eV(1-\frac{1}{4})=-13.6 eV(\frac{3}{4})=-10.2 eV$

While the difference between the levels n=2 and n=3 is

$\Delta E=-13.6 eV(\frac{1}{2^2}-\frac{1}{3^2})=-13.6 eV(\frac{1}{4}-\frac{1}{9})=-13.6 eV(\frac{5}{36})=-1.9 eV$

And so on.

So, the energy difference between adjacent levels decreases as the quantum number increases.

5 0

3 years ago