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Yuri [45]
2 years ago
7

If 125 grams of Cu reacts 75 grams of HNO3, how many grams of Cu(NO3) form?

Chemistry
1 answer:
melisa1 [442]2 years ago
3 0

Answer: 37.5grams of Cu(NO3)2

Cu(1mol) + 2HNO3(2mol) —> Cu(NO3)2 + H2

<em>125 grams of Cu(1mol) reacts with 75 grams of HNO3(2mol)</em>

<em><u>HNO3 is the limiting substance, therefore, 75 grams is the limiting quantity.</u></em>

<em>Therefore, 2mol of HNO3 forms 1mol of Cu(NO3)2</em>

<em>75 grams of HNO3 forms...75grams x 1mol/2mol = 37.5 grams of Cu(NO3)2</em>

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The rate at which the solute dissolves will increase.

Explanation:

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How many joules of heat are required to heat 110 g of aluminum from 52.0 oC to 91.5 oC?
docker41 [41]

Answer:

We need 3910.5 joules of energy

Explanation:

Step 1: Data given

Mass of aluminium = 110 grams

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Final temperature = 91.5 °C

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Step 2: Calculate energy required

Q = m*c*ΔT

⇒with Q = the energy required = TO BE DETERMINED

⇒with m = the mass of aluminium = 110 grams

⇒with c = the specific heat of aluminium = 0.900 J/g°C

⇒with ΔT = the change in temperature = T2 - T1 = 91.5 °C - 52.0 °C = 39.5 °C

Q = 110 grams * 0.900 J/g°C * 39.5

Q = 3910.5 J

We need 3910.5 joules of energy

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Explanation:

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