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3 years ago

A car with a 20-gallon gas tank can go 25 miles on 1 gallon

Chemistry

2 answers:

pickupchik [31]3 years ago

6 0

I think it's "one times".

Diano4ka-milaya [45]3 years ago

3 0

You would have to do 725/25 witch is 29

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How many grams of cobalt (II) nitrate, Co(NO3)2, are required to make a 2.20%(w/v) aqueous solution in a 250 mL volumetric flask

shutvik [7]

Answer:

$\large \boxed{\text{5.50 g}}$

Explanation:

Percent means " per hundred," so % m/V means the grams of something in 100 mL of volume.

$\text{m/V \%} = \dfrac{\text{mass of solute} }{\text{volume of solution}} \times 100 \, \%$

Data:

m/V % = 2.20 %

V of solution = 250 mL

Calculations:

$\text{2.20 \%} = \dfrac{\text{mass of solute} }{\text{250 mL}} \times 100 \, \%\\\\\text{Mass of solute} = \dfrac{2.20\, \% \times \text{250 mL}}{100 \%} = \text{5.50 g}\\\\\text{The mass of Co(NO$_{3}$)$_{2}$ is $\large \boxed{\textbf{5.50 g}}$}$

8 0

3 years ago

Why is that Helium is shown here with the Group II alkali earth metals

Galina-37 [17]

Answer: helium is not a metal nor a non metal it's a noble gas

Explanation:

8 0

4 years ago

What combines to form compounds?

Citrus2011 [14]

Hello! Glad to help.

From what I have learned in my ICP class, molecules combine together to form componds. A compound is any molecule that is made up of two or more different elemental atoms.

Hope this helps you! Anymore questions? Just ask.

6 0

4 years ago

Using the following reaction (depicted using molecular models), large quantities of ammonia are burned in the presence of a plat

Mila [183]

Answer:

17.65 grams of O2 are needed for a complete reaction.

Explanation:

You know the reaction:

4 NH₃ + 5 O₂ --------> 4 NO + 6 H₂O

First you must know the mass that reacts by stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction). For that you must first know the reacting mass of each compound. You know the values of the atomic mass of each element that form the compounds:

N: 14 g/mol
H: 1 g/mol
O: 16 g/mol

So, the molar mass of the compounds in the reaction is:

NH₃: 14 g/mol + 3*1 g/mol= 17 g/mol
O₂: 2*16 g/mol= 32 g/mol
NO: 14 g/mol + 16 g/mol= 30 g/mol
H₂O: 2*1 g/mol + 16 g/mol= 18 g/mol

By stoichiometry, they react and occur in moles:

NH₃: 4 moles
O₂: 5 moles
NO: 4 moles
H₂O: 6 moles

Then in mass, by stoichiomatry they react and occur:

NH₃: 4 moles*17 g/mol= 68 g
O₂: 5 moles*32 g/mol= 160 g
NO: 4 moles*30 g/mol= 120 g
H₂O: 6 moles*18 g/mol= 108 g

Now to calculate the necessary mass of O₂ for a complete reaction, the rule of three is applied as follows: if by stoichiometry 68 g of NH₃ react with 160 g of O₂, 7.5 g of NH₃ with how many grams of O₂ will it react?

$mass of O_{2} =\frac{7.5 g of NH_{3} * 160 g of O_{2} }{68 g of NH_{3} }$

mass of O₂≅17.65 g

<u><em>17.65 grams of O2 are needed for a complete reaction.</em></u>

3 0

3 years ago

Can someone help me with independent variables and dependant variables? I posted a question with the picture on it...please some

Naddik [55]

Answer:

independant=variable that has changed

dependant=variable affected by the change

water=independant, because if you put too much water the dependant that depends on water could die or too little dependant can die (dependant=plants)

Explanation:

6 0

3 years ago