Answer: The Lewis structure of Chloroacetate can be found at the attachment below.
Explanation:
 CH2ClCOO- The chemical compound is called Chloroacetate.
Reference link for the Chloroacetate structure.
https://www.google.com/search?q=lewis+structure+for+CH2ClCOO-&prmd=ivn&sxsrf=ALeKk03mQcLiY-q5pEriMR0_26ZTXLjmJg:1589680325594&source=lnms&tbm=isch&sa=X&ved=2ahUKEwjfxPPY5LnpAhVloXEKHeAwD-wQ_AUoAXoECA4QAQ&cshid=1589680746615&biw=360&bih=559&dpr=3#
 
        
             
        
        
        
OH
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Answer:
Concentration solution A was 0.5225 M
Explanation:
10.00 mL of solution A was diluted to 50.00 mL and yields 50.00 mL of solution B
According to laws of dilution-      
where,  and
 and  are concentration of solution A and B respectively
 are concentration of solution A and B respectively
 and
 and  are volumes of solution A and B respectively
 are volumes of solution A and B respectively
Here  = 0.1045 M,
 = 0.1045 M,  = 50.00 mL and
 = 50.00 mL and  = 10.00 mL
 = 10.00 mL
Hence, 
So, concentration solution A was 0.5225 M
 
        
             
        
        
        
Answer:
25.157 cm³
Explanation:
Data Given:
Mass of Sugar (m) = 40g
Density of sugar given in literature = 1.59 g/cm³
Volume of Sugar = ?
The formula will be used is 
                               d = m/v ........................................... (1)
where 
D is density
m is the mass
v is the volume
So 
Rearrange the Equation (1)
                               d x v = m
                                v = m/ d         ................................................ (2)
put the given values in Equation  (2)
                        v = 40g / 1.59 g/cm³
                        v = 25.157 cm³
volume of 40 g of sugar = 25.157 cm³