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julsineya [31]
3 years ago
6

How do paved parking lots and roads with concrete or asphalt affect water flow on the land?

Physics
1 answer:
harina [27]3 years ago
8 0
On the regular ground, water usually seeps in to the soil, which has a number of benefits for the wildlife in that area. However, with asphalt and concrete, there is no soft and absorbent soil to take in the water, so it just keeps flowing down to the lowest part of land it can. Additionally, some water runoff can carry fertilizer and other harmful chemicals with it in to the oceans and lakes it’s dumped in, which harms the ecosystem in them as well.
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Based on the speed, the questio the speed, the river, the speed of your boat relative to the water , and the distance across the
ANTONII [103]

Answer:

The velocity of a particle relative to S is equal to its velocity relative to S′ plus the velocity of S′ relative to S. We can extend Equation 4.35 to any number of reference frames. For particle P with velocities →vPA, →vPB, and →vPC in frames A, B, and C, →vPC=→vPA+→vAB+→vBC.

Explanation:

Resultant Velocity. Multiply the acceleration by the time the object is being accelerated. For example, if an object falls for 3 seconds, multiply 3 by 9.8 meters per second squared, which is the acceleration from gravity. The resultant velocity in this case is 29.4 meters per second.

6 0
3 years ago
Given a particle that has the velocity v(t) = 3 cos(mt) = 3 cos (0.5t) meters, a. Find the acceleration at 3 seconds. b. Find th
DiKsa [7]

Answer:

a.\rm -1.49\ m/s^2.

b. \rm 50.49\ m.

Explanation:

<u>Given:</u>

  • Velocity of the particle, v(t) = 3 cos(mt) = 3 cos (0.5t) .

<h2>(a):</h2>

The acceleration of the particle at a time is defined as the rate of change of velocity of the particle at that time.

\rm a = \dfrac{dv}{dt}\\=\dfrac{d}{dt}(3\cos(0.5\ t ))\\=3(-0.5\sin(0.5\ t.))\\=-1.5\sin(0.5\ t).

At time t = 3 seconds,

\rm a=-1.5\sin(0.5\times 3)=-1.49\ m/s^2.

<u>Note</u>:<em> The arguments of the sine is calculated in unit of radian and not in degree.</em>

<h2>(b):</h2>

The velocity of the particle at some is defined as the rate of change of the position of the particle.

\rm v = \dfrac{dr}{dt}.\\\therefore dr = vdt\Rightarrow \int dr=\int v\ dt.

For the time interval of 2 seconds,

\rm \int\limits^2_0 dr=\int\limits^2_0 v\ dt\\r(t=2)-r(t=0)=\int\limits^2_0 3\cos(0.5\ t)\ dt

The term of the left is the displacement of the particle in time interval of 2 seconds, therefore,

\Delta r=3\ \left (\dfrac{\sin(0.5\ t)}{0.05} \right )\limits^2_0\\=3\ \left (\dfrac{\sin(0.5\times 2)-sin(0.5\times 0)}{0.05} \right )\\=3\ \left (\dfrac{\sin(1.0)}{0.05} \right )\\=50.49\ m.

It is the displacement of the particle in 2 seconds.

7 0
4 years ago
What is the carrying capacity of an ecosystem
abruzzese [7]

n ecological terms, the carrying capacity of an ecosystem is the size of the population that can be supported indefinitely upon the available resources and services of that ecosystem. Living within the limits of an ecosystem depends on three factors:

<span>the amount of resources available in the ecosystem,the size of the population, and<span>the amount of resources each individual is consuming.</span></span>
8 0
3 years ago
20. A 0.145 kg mass of tungsten at 130.0 °C is placed in a 0.502 kg of water at 22.0 °C. The mixture reaches equilibrium at 28.6
zepelin [54]
MaCa∆Tb = MbC∆Tb
Where m is the mass of a compound
<span> C is the specific heat of a compound 
</span>∆T is the change of temperature of the compound  
<span> (0.502 kg water)(4180 j/kg C)( 28.6 – 22 C) = ( 0.145 kg tungsten) ( C ) ( 130 – 28.6 C) 
</span>Solve for C
<span>C = 941.9 J /kg C </span>
8 0
3 years ago
What is 18000 expressed in scientific notation​
Vikki [24]
1.8x 10^4
This is 18000 expressed in scientific notation.
8 0
4 years ago
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