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3 years ago

How do paved parking lots and roads with concrete or asphalt affect water flow on the land?

1 answer:

8 0

On the regular ground, water usually seeps in to the soil, which has a number of benefits for the wildlife in that area. However, with asphalt and concrete, there is no soft and absorbent soil to take in the water, so it just keeps flowing down to the lowest part of land it can. Additionally, some water runoff can carry fertilizer and other harmful chemicals with it in to the oceans and lakes it’s dumped in, which harms the ecosystem in them as well.

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Suppose that a constant force is applied to an object. Newton's Second Law of Motion states that the acceleration of the object

omeli [17]

(9 kg)(5 m/s^2) = M(3 m/s^2)
that the acceleration of the object varies inversely with its mass.

4 0

3 years ago

Look at the rock sitting on the hill in the picture above. Gravity should make the rock slide down the hill. What force is actin

nordsb [41]

Look at the rock sitting on the hill in the picture above. Gravity should make the rock slide down the hill. What force is acting to balance gravity,keeping the rock in place? - D. friction
Centripetal force and momentum have to do with movement. Gravity cannot balance gravity.

5 0

3 years ago

Read 2 more answers

En un rio una Onda viaja con una velocidad de propagación de 50 m/s con una longitud de Onda de 40 metros. Hallar la frecuencia

sattari [20]

Answer:

Frequencia = 1.25 Hz

Explanation:

Dados los siguientes datos;

Velocidad = 50 m/s
Longitud de onda = 40 metros

Para encontrar la frecuencia de la onda;

Matemáticamente, la velocidad de una onda viene dada por la fórmula;

$Velocidad = Longitud \; de \; onda * Frequencia$

Haciendo de la frecuencia el tema de la fórmula, tenemos;

$Frequencia = \frac {Velocidad}{Longitud \; de \; onda}$

Sustituyendo en la fórmula, tenemos;

$Frequencia = \frac {50}{40}$

Frequencia = 1.25 Hz

7 0

3 years ago

One watt is A. equal to one kilogram per second B. the power that can be delivered by an average horse C. the same as one-foot p

Naddik [55]

Answer:

D. the proper replacement unit for one joule per second

Explanation:

When energy is divided by the time the energy was used we get power

$P=\dfrac{E}{t}\\\Rightarrow P=\dfrac{mv^2}{t}\\\Rightarrow P=\dfrac{kg(\dfrac{m^2}{s^2})}{s}\\\Rightarrow P=kg(\dfrac{m^2}{s^2})}\times \dfrac{1}{s}\\\Rightarrow P=\dfrac{kgm^2}{s^3}$

$kg\dfrac{m^2}{s^2}=Joule$

$P=\dfrac{kgm^2}{s^3}$

So, the answer is D. the proper replacement unit for one joule per second

8 0

3 years ago

Please answer asignment due today

Iteru [2.4K]

Answer:

Give me some time okkkk

4 0

3 years ago