Answer:
The velocity of a particle relative to S is equal to its velocity relative to S′ plus the velocity of S′ relative to S. We can extend Equation 4.35 to any number of reference frames. For particle P with velocities →vPA, →vPB, and →vPC in frames A, B, and C, →vPC=→vPA+→vAB+→vBC.
Explanation:
Resultant Velocity. Multiply the acceleration by the time the object is being accelerated. For example, if an object falls for 3 seconds, multiply 3 by 9.8 meters per second squared, which is the acceleration from gravity. The resultant velocity in this case is 29.4 meters per second.
Answer:
a.
b. 
Explanation:
<u>Given:</u>
- Velocity of the particle, v(t) = 3 cos(mt) = 3 cos (0.5t) .
<h2>
(a):</h2>
The acceleration of the particle at a time is defined as the rate of change of velocity of the particle at that time.
At time t = 3 seconds,
<u>Note</u>:<em> The arguments of the sine is calculated in unit of radian and not in degree.</em>
<h2>
(b):</h2>
The velocity of the particle at some is defined as the rate of change of the position of the particle.
For the time interval of 2 seconds,
The term of the left is the displacement of the particle in time interval of 2 seconds, therefore,
It is the displacement of the particle in 2 seconds.
n ecological terms, the carrying capacity of an ecosystem is the size of the population that can be supported indefinitely upon the available resources and services of that ecosystem. Living within the limits of an ecosystem depends on three factors:
<span>the amount of resources available in the ecosystem,the size of the population, and<span>the amount of resources each individual is consuming.</span></span>
MaCa∆Tb = MbC∆Tb
Where
m is the mass of a compound
<span>
C
is the specific heat of a compound
</span>∆T is the change of temperature of the compound
<span>
(0.502
kg water)(4180 j/kg C)( 28.6 – 22 C) = ( 0.145 kg tungsten) ( C ) ( 130 – 28.6
C)
</span>Solve
for C
<span>C
= 941.9 J /kg C </span>
1.8x 10^4
This is 18000 expressed in scientific notation.
