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3 years ago

Find the vector parallel to the resultant of the vector A=i +4j-2k and B=3i-5j+k

Physics

2 answers:

Zinaida [17]3 years ago

8 0

Answer:

2008

Explanation:

2000+3+5======2008

valkas [14]3 years ago

6 0

Answer:

$8\hat i-2\hat j-2\hat k$

Explanation:

Vectors in 3D

Given a vector

$\vec P = P_x\hat i+P_y\hat j+P_z\hat k$

A vector $\vec Q$ parallel to $\vec P$ is:

$\vec Q = k.\vec P$

Where k is any constant different from zero.

We are given the vectors:

$\vec A = \hat i+4\hat j-2\hat k$

$\vec B = 3\hat i-5\hat j+\hat k$

It's not specified what the 'resultant' is about, we'll assume it's the result of the sum of both vectors, thus:

$\vec A +\vec B = \hat i+4\hat j-2\hat k + 3\hat i-5\hat j+\hat k$

Adding each component separately:

$\vec A +\vec B = 4\hat i-\hat j-\hat k$

To find a vector parallel to the sum, we select k=2:

$2(\vec A +\vec B )= 8\hat i-2\hat j-2\hat k$

Thus one vector parallel to the resultant of both vectors is:

$\mathbf{8\hat i-2\hat j-2\hat k}$

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2 years ago

On a trolley ride around an amusement park, a child travelled from one signpost to a second signpost at a constant speed of 125

Tomtit [17]

Answer:

Explanation:

Speed given = 125 m /min

125 /60 m /s

In 450 second it will travel

= 450 x 125 / 60

=937.5 m.

As the distance is covered in less than 450 seconds , The distance must be less than 937.5 m

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2 years ago

A small object of mass 3.82 g and charge -16.5 µC is suspended motionless above the ground when immersed in a uniform electric f

horrorfan [7]

Answer:

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Explanation:

The diagram well illustrate all the forces acting on the mass. The weight is acting downward and the force is acting upward in other to balance the weight.since the question says it is motionless, then indeed the forces are balanced.

First we determine the downward weight using

$W=mg\\g=9.81m/s^{2}$

Hence for a mass of 3.82g 0r 0.00382kg we have the weight to be

$W=0.00382kg*9.81m/s^{2}$

$W=0.0375N$

To calculate the electric field,

$E=f/q\\E=0.0375/16.5*10^{-6} \\E=2271.16N/C$

Since the charge on the mass is negative, in order to generate upward force, there must be a like charge below it that is repelling it, Hebce we can conclude that the electric field lines are upward.

Hence the magnitude of the electric force is 2271.16N/C and the direction is upward

4 0

3 years ago

Find the vector parallel to the resultant of the vector A=i +4j-2k and B=3i-5j+k​

Find the vector parallel to the resultant of the vector A=i +4j-2k and B=3i-5j+k