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Dmitriy789 [7]
3 years ago
15

Find the vector parallel to the resultant of the vector A=i +4j-2k and B=3i-5j+k​

Physics
2 answers:
Zinaida [17]3 years ago
8 0

Answer:

2008

Explanation:

2000+3+5======2008

valkas [14]3 years ago
6 0

Answer:

8\hat i-2\hat j-2\hat k

Explanation:

<u>Vectors in 3D</u>

Given a vector

\vec P = P_x\hat i+P_y\hat j+P_z\hat k

A vector \vec Q parallel to \vec P is:

\vec Q = k.\vec P

Where k is any constant different from zero.

We are given the vectors:

\vec A = \hat i+4\hat j-2\hat k

\vec B = 3\hat i-5\hat j+\hat k

It's not specified what the 'resultant' is about, we'll assume it's the result of the sum of both vectors, thus:

\vec A +\vec B = \hat i+4\hat j-2\hat k + 3\hat i-5\hat j+\hat k

Adding each component separately:

\vec A +\vec B = 4\hat i-\hat j-\hat k

To find a vector parallel to the sum, we select k=2:

2(\vec A +\vec B )= 8\hat i-2\hat j-2\hat k

Thus one vector parallel to the resultant of both vectors is:

\mathbf{8\hat i-2\hat j-2\hat k}

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the speed of light in a certain medium is 0.6c. find critical angle , if the index of refraction is 1.67​
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