Answer:
distance between the ships changing 29.255 knot
Explanation:
Given data
time = noon to 5 pm = 5 hours
A = 50 nautical miles due west of B
A = sailing west at 22 knots
B = sailing north at 20 knots
to find out
How fast is the distance between the ships changing
solution
we consider a to b distance is z and at noon ship at 90 degree angle of AB at x and y distance from AB respectively
so here z² = x² + y² ..............1
and 2z z' = 2x x' + 2y y'
so z' = ( x x' + y y' ) / z
and after 5 hours
x = 50 + 22(t) = 50 + 22(5) = 160
y = 20(t) = 20 (5) = 100
so from equation 1
z² = x² + y²
z² = 160² + 100²
z = ![\sqrt{25600+10000}](https://tex.z-dn.net/?f=%5Csqrt%7B25600%2B10000%7D)
z = 188.68
so z' = ( x x' + y y' ) / z
z' = ( 160 (22) + 100(20) ) / 188.68
z' = 29.255
distance between the ships changing 29.255 knot
Answer:
Explanation:
a ) Height to be cleared = 5 - 1.6 = 3.4 m
Horizontal distance to be cleared = 5 m .
angle of throw = 56°
here y = 3.4 , x = 5 , θ = 56
equation of trajectory
y = x tanθ - 1/2 g ( x/ucosθ)²
3.4 = 5 tan56 - 1/2 g ( 5/ucos56)²
3.4 = 7.4 - 122.5 / .3125u²
122.5 / .3125u² = 4
u² = 98
u = 9.9 m /s
Range = u² sin 2 x 56 / g
= 9.9 x 9.9 x .927 / 9.8
= 9.27 m
horizontal distance be-yond the fence will the rock land on the ground
= 9.27 - 5
= 4.27 m
Chromosomes that's the answer
Answer:
Explanation:
Potential energy is the energy stored within an object, due to the object's position, arrangement or state
Answer:
![F=1N](https://tex.z-dn.net/?f=F%3D1N)
Explanation:
Conceptual analysis
To solve this problem we apply Newton's second law:
The acceleration of an object is proportional to the force F acting on it and inversely proportional to its mass m.
a = F / m
Where,
F = m * a Formula (1)
F: Force in Newtons (N)
m: mass in kg
a: acceleration in m/(s^2)
a = v / t Formula (2)
v: speed in m/s
t: time in seconds (s)
Known information
We know the following data:
m = 1kg
v = 1 m/s
t = 1s
Development of the problem:
In the Formula (2): ![a = \frac{\frac{1m}{s}}{1s} = 1 \frac{m}{s^2}](https://tex.z-dn.net/?f=a%20%3D%20%5Cfrac%7B%5Cfrac%7B1m%7D%7Bs%7D%7D%7B1s%7D%20%3D%201%20%5Cfrac%7Bm%7D%7Bs%5E2%7D)
In the Formula (1): ![F=1kg* 1 \frac{m}{s^2}=1N](https://tex.z-dn.net/?f=F%3D1kg%2A%201%20%5Cfrac%7Bm%7D%7Bs%5E2%7D%3D1N)