To solve this problem it is necessary to consider two concepts. The first of these is the flow rate that can be defined as the volumetric quantity that a channel travels in a given time. The flow rate can also be calculated from the Area and speed, that is,
Q = V*A
Where,
A= Cross-sectional Area
V = Velocity
The second concept related to the calculation of this problem is continuity, which is defined as the proportion that exists between the input channel and the output channel. It is understood as well as the geometric section of entry and exit, defined as,
Our values are given as,
Re-arrange the equation to find the first ratio of rates we have:
The second ratio of rates is
Explanation:
F=m(v-u)/t
F=2N
m=2kg
t=2s
2=2(v-u)/2
cross multiply
2*2=2(v-u)
4=2(v-u)
4/2=v-u
v-u=2m/s
v-u is the change is velocity.
1 horsepower is equal to 746 W, so the power of the engine is
The power is also defined as the energy E per unit of time t:
Where the energy corresponds to the work done by the engine, which is
. Re-arranging the formula, we can calculate the time t needed to do this amount of work:
The process which involves plants to cause weathering to a seed that falls into a crack in a rock therefore, breaking apart the rock is called Mechanical weathering.
<h3>
Mechanical weathering</h3>
This is defined as the set of weathering processes that break apart rocks into particles (sediment) through physical processes. The most common form of mechanical weathering is the freeze-thaw cycle. Water seeps into holes and cracks in rocks then the water freezes and expands, therefore making the holes larger eventually making the rock split apart.
Read more on Mechanical weathering:
brainly.com/question/857495
