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2 years ago

If the Moon had twice as much mass and still orbits Earth at the same distance, ocean bulges on Earth would be

1 answer:

6 0

Ocean bulges on Earth would be bigger if the Moon had twice as much mass and yet orbited the planet at the same distance. Option B is correct.

<h3>What is ocean bludge?</h3>

The fluid and moveable ocean water are drawn towards the moon by the gravitational attraction between the moon and the Earth.

The ocean nearest to the moon experiences a bulge as a result, and as the Earth rotates, the affected seas' locations shift.

The Moon's bulges in the oceans would be larger if it had twice the mass and orbited Earth at the same distance.

Hence option B is corect.

To learn more about the ocean bulge refer;

brainly.com/question/14373016

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Phileas Fogg, the character who went around the world in 80 days, was very fussy about his bathwater temperature. It had to be e

Allisa [31]

Answer:

The mass of the Al-duckie should be 30 kg.

Explanation:

We will use the first law of thermodynamics:

ΔU = m·Cv·ΔT

Since the specific heat of water is 4.185 J(gºC), the change in the water's internal energy would be:

ΔU = 100 kg · 4.185 J(gºC) · (42ºC - 38ºC) = 1674 KJ

Given that no heat is lost, all the internal energy that the water loses while cooling down will transfer to the duckie. So, if the duckie has ΔU = 1674 KJ and its final temperature is the desired 38 ºC, we can calculate its mass using the first law again:

$m=\frac{\Delta{U}}{Cv{\Delta{T}}}=\frac{1674}{0.9*[38-(-24)]}=30Kg$

5 0

3 years ago

A uniform rod of length 50cm and mass 0.2kg is placed on a fulcrum at a distance of 40cm from the left end of the rod. At what d

oksano4ka [1.4K]

Answer:

x = 45 cm

Explanation:

Given that,

The length of a rod, L = 50 cm

Mass, m₁ = 0.2 kg

It is at 40cm from the left end of the rod.

We need to find the distance from the left end of the rod should a 0.6kg mass be hung to balance the rod.

The centre of mass of the rod is at 25 cm.

Taking moments of both masses such that,

$15\times 0.2=x\times 0.6\\\\x=\drac{3}{0.6}\\\\x=5\ cm$

The distance from the left end is 40+5 = 45 cm.

Hence, at a distance of 45 cm from the left end it will balance the rod.

5 0

3 years ago

The kinetic energy of a 10 Kg ball rolling at 10 meters per second is how many joules

Ulleksa [173]

Answer: 500 joules

Explanation:

Given that

Mass of ball = 10kg

kinetic energy = ?

velocity of the ball = 10m/s

Kinetic energy is the energy possessed by a moving object. It is measured in joules, and depends on the mass (m) of the object and the velocity (v) by which it moves

i.e K.E = 1/2mv²

K.E = 1/2 x 10kg x (10m/s)²

K.E = 0.5 x 10kg x (10m/s)²

K.E = 5 x 100

K.E = 500 joules

Thus, the kinetic energy of the ball is 500 joules

6 0

3 years ago

2. If a cyclist in the Tour de France traveled southwest a distance of 12,250 meters in one hour, what would the velocity of the

Luda [366]

Answer:

Explanation:

5 0

3 years ago

What voltage battery would you need to send 2.5A of current through a light bulb of resistance 3.6 ohm

nadezda [96]

<h3><u>Given</u> :</h3>

Current flow light bulb = 2.5 $\sf{A}$

Resistance of light bulb = 3.6Ω

We have to find voltage of battery $.$

<h3><u>Solution</u> :</h3>

➠ As per ohm's law, current flow through a conductor is directly proportional to the applied potential difference.

➝ V ∝ I

➝ <u>V = I × R</u>

Where, R is the resistance of conductor.

⇒ V = I × R

⇒ V = 2.5 × 3.6

⇒ <u>V = 9 volt</u>

8 0

3 years ago