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snow_lady [41]
3 years ago
7

Please help me this is important!

Physics
1 answer:
Mariulka [41]3 years ago
4 0
145 Grams!
It asks for the “Total Mass” basically asking to add, If you add 20 to 125, you get 145! Correct me if im wrong
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Plz help i need help on my homework
tatiyna
The resultant force is 4 N to the right.
6 0
4 years ago
Read 2 more answers
If R1 = 6, R2 = 2 and VAΓ = 16 Find Roλ, I, VAB, VAΓ​
erica [24]

Answer:

<em>Rt = 8 ohm</em>

<em>I = 2 A</em>

<em>Vab = 12 V</em>

<em>VbΓ = 4 V</em>

<em>VaΓ = 16 V</em>

Explanation:

<u>Electric Circuits</u>

We'll apply Ohm's formula to solve the circuit shown on the image:

V = R.I

Where V is the voltage, R is the resistance, and I is the current.

The circuit has two resistances connected in series, thus the total resistance is:

Rt = R1 + R2 = 6 ohm + 2 ohm = 8 ohm

Now the current is:

\displaystyle I=\frac{V}{Rt}

\displaystyle I=\frac{16}{8}

I = 2 A

The voltages are calculated below:

Vab = R1 * I = 6 ohm * 2 A = 12 V

VbΓ = R2 * I = 2 ohm * 2 A = 4 V

VaΓ = Vab + VbΓ = 12 V + 4 V = 16 V

8 0
3 years ago
Energy can be used to do which of the following things? Select one: Make something hotter Make something move Lift something up
Vlad [161]
All three of those are correct.
7 0
4 years ago
How does kinetic energy affect the stopping distance of a vehicle traveling at 30 mph compared to the same vehicle traveling at
slavikrds [6]
So the answers to your questions are the following:
#2 The Kinetic Energy is equals to the work done to stop. 
#3 The mass is directly proportional to the stopping distance of the car.
#4 Speed should be decrease in order the car to prepare on the sharp curves.
#5 It depends to the speed and acceleration of the car and also its inertia which would be affected by the sudden stop of the vehicles
5 0
3 years ago
When a certain gas under a pressure of 4.90 106 pa at 20.0°c is allowed to expand to 3.00 times its original volume, its final p
Elina [12.6K]

As per question the initial states of the gases are given as

INITIAL STATE:                                          FINAL STATE:

p_{1} =4.90106 pa                       p_{2} =1.06106 pa

v_{1} =v[say]                                 v_{2} =3v[say]

T_{1} =20 degree celcius  =293 K              T_{2} =?

AS  per combined gas equation obtained from the combination of Boyle's law and Charles law [Basic ideal gas laws]

              \frac{p_{1} v_{1} }{T_{1} } =\frac{p_{2}v_{2}  }{T_{2} }

Hence T_{2} =\frac{p_{2} v_{2}T_{1}  }{p_{1} v_{1} }

                    =\frac{1.06106*3v*293}{4.90106*v}

                    =190.3 K [ANS]

                 

   

6 0
3 years ago
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