Question

a chemist wishes to mix some pure acid with some water to produce 16L of a solution that is 30% acid how much pure acid and how much water should be mixed?

Answer 1

Answer: The volume of acid and water that must be mixed will be 4.8 L and 11.2 L

Explanation:

We are given:

Volume of mixture = 16 L

Percent of acid present = 30 %

Calculating the percentage of acid present in the mixture:

$\Rightarrow 16\times \frac{30}{100}=4.8L$

The mixture is made entirely of acid and water.

Volume of acid in the mixture = 4.8 L

Volume of water in the mixture = 16 - 4.8 = 11.2 L

Hence, the volume of acid and water that must be mixed will be 4.8 L and 11.2 L