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3 years ago

I’m just checking my answer. Thanks!

Chemistry

1 answer:

OLEGan [10]3 years ago

5 0

Answer:

78.89 g of CO is required.

Explanation:

$Fe_{2}O_{3}+3CO\longrightarrow3CO_{2}+2Fe$

Fe = 55.85 g/mol

O = 15.99 g/mol

C = 12.01 g/mol

2 moles of Fe is produced on reacting 1 mole of $Fe_{2}O_{3}$ .

2 moles of Fe is produced on reacting 3 moles of CO.

$Weight\:of\:one\:mole\:of\:Fe_{2}O_{3}=2\times55.85+3\times15.99=159.67g\\$

$Weight\:of\:one\:mole\:of\:CO=12.01+15.99=28g$

$The\:weight\:of\:two\:moles\:of\:Fe=2\times55.85=111.7g\\111.7g\:of\:Fe\:is\:produced\:by\:reacting\:(3\times28=)84g\:of\:CO\\\\104.9g\:of\:Fe\:is\:produced\:on\:reacting=\frac{84\times104.9}{111.7}=78.89g\:of\:CO\\$

Hence, 78.89 g of CO on reacting with excess of ferric oxide will produce 104.9 g of Fe.

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An atom of helium has a radius of 31. pm and the average orbital speed of the electrons in it is about 4.4x 10 m/s Calculate the

otez555 [7]

The question is incomplete, here is the complete question:

An atom of helium has a radius of 31. pm and the average orbital speed of the electrons in it is about $4.4\times 10^6m/s$ . Calculate the least possible uncertainty in a measurement of the speed of an electron in an atom of helium. Write your answer as a percentage of the average speed, and round it to 2 significant digits

Answer: The percentage of average speed is 41 %

Explanation:

We are given:

Radius of helium atom = 31 pm = $31\times 10^{-12}m$ (Conversion factor: $1m=10^{12}pm$ )

So, diameter of helium atom = $(2\times r)=(2\times 31\times 10^{-12})=64\times 10^{-12}m$

The diameter of the atom will be equal to the uncertainty in position.

The equation representing Heisenberg's uncertainty principle follows:

$\Delta x.\Delta p=\frac{h}{2\pi}$

where,

$\Delta x$ = uncertainty in position = d = $64\times 10^{-12}m$

$\Delta p$ = uncertainty in momentum = $m\Delta v$

m = mass of electron = $9.1095\times 10^{-31}kg$

h = Planck's constant = $6.627\times 10^{-34}kgm^2/s^2$

Putting values in above equation, we get:

$64\times 10^{-12}m\times 9.1095\times 10^{-31}kg\times \Delta v=\frac{6.627\times 10^{-34}kgm^2/s}{2\times 3.14}\\\\\Delta v=\frac{6.627\times 10^{-34}kgm^2/s^2}{2\times 3.14\times 64\times 10^{-12}m\times 9.1095\times 10^{-31}kg}=1.81\times 10^6m/s$

To calculate the percentage of average speed, we use the equation:

$\text{Percentage of the average speed}=\frac{\text{Uncertainty in velocity}}{\text{Average orbital speed}}\times 100$

We are given:

Average orbital speed = $4.4\times 10^6m/s$

Putting values in above equation, we get:

$\text{Percentage of the average speed}=\frac{1.81\times 10^6m/s}{4.4\times 10^6m/s}\times 100\\\\\text{Percentage of the average speed}=41.\%$

Hence, the percentage of average speed is 41 %

3 0

4 years ago

Determine the ph of a 0.188 m nh3 solution at 25°c. the kb of nh3 is 1.76 × 10-5.

Ber [7]

When NH3 is dissolved in water, it dissociates partially producing NH4+ ions and OH- ions. It has an equation:
NH3 + H2O → NH4+ + OH-

We use the Kb expression to determine the [OH-] concentration,

Kb = [NH4+] [OH-] /* [NH3] 

We can write NH4+ as OH- since they are of equal ratio.
(1.76*10^-5) = [OH-]² / 0.188
[OH-]² = 3.3088*10^-6 
[OH-] = 1.819*10^-3 

We calculate for H+ concentration as follows:

[H+] [OH-] = 10^-14 
[H+] = 10^-14 / [OH-] 
[H+] = 10^-14 / (1.819*10^-3) 
[H+] = 5.50*10^-12 

pH = -log [H+] 
pH = -log (5.5*10^-12) 
pH = 11.26

4 0

3 years ago

For which of the following equilibria does Keq= [O2]?

dybincka [34]

Its A if youre doing plato

8 0

4 years ago

Which of the following characteristics best describe the properties of liquids? Select all that apply.

Assoli18 [71]

Answer:

No definite shape

Explanation: