Conc = moles / Vol you have C but need to find moles
moles KCl = mass / molar mass
25 g / 74.55 g,p;
0.335 moles
So rearrange the formula to find volume. Vol = moles / Conc
0.335 moles / 0.750 mol / L = 0.447 L or 447 mL
The answer in this question is 447 mL.
Answer: 448 g of
will be required to completely react with 784g moles of CO(g) during this reaction.
Explanation:
To calculate the moles :
The balanced chemical equation is:
According to stoichiometry :
2 moles of
require = 1 mole of
Thus 28 moles of
will require=
of
Mass of
Thus 448g of
will be required to completely react with 784g moles of CO(g) during this reaction.
Without an external doing work, heat will always flow from a hotter to cooler object. Two objects of different tempatures always interact. There are three different ways for heat to flow from one object to another. They are conduction, convention, and radiation.
The correct answer is B. A homogeneous mixture has the same properties for every part of the mixture, so the quality of the material is consistent.
Explanation:
In a homogenous mixture, all the components are equally integrated; this means the final result in the case of a material is a material that looks uniform and also has the same properties in every part of section. This homogeneity and consistency are especially important if you are testing the properties of the material or using it for a specific application because if you use a homogenous mixture the quality and properties will be consistent and thus you can obtain consistent results.
Answer: Dissociation constant of the acid is
.
Explanation: Assuming the acid to be monoprotic, the reaction follows:

pH of the solution = 6
and we know that
![pH=-log([H^+])](https://tex.z-dn.net/?f=pH%3D-log%28%5BH%5E%2B%5D%29)
![[H^+]=antilog(-pH)](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3Dantilog%28-pH%29)
![[H^+]=antilog(-6)=10^{-6}M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3Dantilog%28-6%29%3D10%5E%7B-6%7DM)
As HA ionizes into its ions in 1 : 1 ratio, hence
![[H^+]=[A^-]=10^{-6}M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D%5BA%5E-%5D%3D10%5E%7B-6%7DM)
As the reaction proceeds, the concentration of acid decreases as it ionizes into its ions, hence the decreases concentration of acid at equilibrium will be:
![[HA]=[HA]-[H^+]](https://tex.z-dn.net/?f=%5BHA%5D%3D%5BHA%5D-%5BH%5E%2B%5D)
![[HA]=0.1M-10^{-6}M](https://tex.z-dn.net/?f=%5BHA%5D%3D0.1M-10%5E%7B-6%7DM)
![[HA]=0.09999M](https://tex.z-dn.net/?f=%5BHA%5D%3D0.09999M)
Dissociation Constant of acid,
is given as:
![K_a=\frac{[A^-][H^+]}{HA}](https://tex.z-dn.net/?f=K_a%3D%5Cfrac%7B%5BA%5E-%5D%5BH%5E%2B%5D%7D%7BHA%7D)
Putting values of
in the above equation, we get


Rounding it of to one significant figure, we get
