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Mariulka [41]
3 years ago
7

Can someone check if what i wrote so far makes sense and if i made a mistake.

Physics
2 answers:
Serjik [45]3 years ago
7 0
I don't really know what it's about but everything looks okay to me. There might be some mistakes on the last sentence but i'm not completely sure.
garri49 [273]3 years ago
5 0
It looks great, except, I would rewrite the first sentence as "Everett knew it was dangerous to be within close proximity to a cheetah". Also, in the second sentence, I would get rid of the words "at the moment". They aren't really necessary. That's all. Everything else looks perfect. Good job introducing the subject, by the way.
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If a drop is to be deflected a distance d = 0.350 mm by the time it reaches the end of the deflection plate, what magnitude of c
Sloan [31]

Answer:

q = 4.87 X 10^ -14 C

Explanation:

As d=0.350 mm

The ink drop will be accelerated by the electric field between the plates:

a = F/m

d = a(D0 / v)^2 / 2 ...... 1

a = qE/m ............... 2

Substituting 2  into 1:

d = (qE/m)(D0 / v)^2 / 2

q = 2mdv^2 / [E(D0)^2]

q = 2(1.00e-11 kg)(3.50e-4 m)(15.0 m/s)^2 / [(7.70e4 N/C)(2.05e-2 m)^2]

q = 4.87e-14 C

6 0
3 years ago
block is attached to an oscillating spring. The function below shows its position (cm) vs. time (s). What is the angular frequen
faltersainse [42]

Answer:

Angular frequency is 20 rad/s.      

Explanation:

Given that,

A block is attached to an oscillating spring. The function below shows its position (cm) vs. time (s) is given by :

x(t)=1.5\cos(20\ t).....(1)

The general equation of oscillating particle is given by :

x(t)=A\cos(\omega t).......(2)

Compare equation (1) and (2) we get :

\omega=20\ rad/s

So, the angular frequency of the oscillation is 20 rad/s.

7 0
3 years ago
A taxi is travelling at 15 m/s. Its driver accelerates with
Hitman42 [59]
If we assume that the acceleration is constant, we can use on the kinematic equations:

Vf = Vi + a*t = 15 + 3*4 = 27 m/s
6 0
3 years ago
Two forces, F1 = -3000 N and F2 = +1500 N acts on a plane horizontally. The craft is moving with a constant velocity of -850 m/s
jonny [76]

Because the net force must be zero, we conclude that the magnitude of the force is 1500 newtons, and the direction is in the positive axis.

<h3>What is the magnitude and direction of the third force?</h3>

By Newton's laws, we know that if the net force applied to an object is different than zero, then the object is accelerated.

In this case, we know that the object moves with constant velocity, so there is no acceleration, meaning that the net force is equal to zero.

Then we must have:

F1 + F2 + F3 = 0N

Replacing F1 and F2 we get:

-3000 N + 1500N + F3 = 0

F3 = 3000N - 1500 N = 1500N

Then the magnitude of the force is 1500 newtons, and the direction is in the positive axis.

If you want to learn more about Newton's laws, you can read:

brainly.com/question/10454047

8 0
2 years ago
What best describes the angle between a changing electric field and the electromagnetic wave produced by it?
MrRa [10]

The correct ans is 1.

A changing electric field produces a changing magnetic field which in turn produces a changing electric field. This means that the source has created a changing electric and magnetic fields, perpendicular to each other, that travel away from the source. Electric field, magnetic field and the EM wave are perpendicular to each other. This gives electromagnetic waves their transverse nature.

7 0
3 years ago
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