Impulse, denoted as J, is defined by the change in momentum. Since we have our initial and our final, we can solve for the change in momentum.
Can someone check if what i wrote so far makes sense and if i made a mistake.
2 answers:
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Answer:
The minimum frequency required to ionize the photon is 111.31 × Hertz
Given:
Energy = 378
To find:
Minimum frequency of light required to ionize magnesium = ?
Formula used:
The energy of photon of light is given by,
E = h v
Where E = Energy of magnesium
h = planks constant
v = minimum frequency of photon
Solution:
The energy of photon of light is given by,
E = h v
Where E = Energy of magnesium
h = planks constant
v = minimum frequency of photon
738 × = 6.63 ×
× v
v = 111.31 × Hertz
The minimum frequency required to ionize the photon is 111.31 × Hertz