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ipn [44]
3 years ago
12

A physics instructor wants to project a spectrum of visible-light colors from 400 nm to 700 nm as part of a classroom demonstrat

ion. She shines a beam of white light through a diffraction grating that has 700 lines per mm, projecting a pattern on a screen 2.9 m behind the grating. How wide is the spectrum corresponding to m=1?
Physics
1 answer:
Zanzabum3 years ago
6 0

Answer:

Explanation:

Given

Slit\ width=d=\frac{10^{-3}}{700}=1.428\times 10^{-6} m

Distance of screen from light source D=2.9 m

\lambda _1=400 nm

\lambda _2=700 nm

we know in slit Experiment

d\sin \theta=n\lambda, where \theta=angle between the path and a line from the slits to the screen

1.428\times 10^{-6}\cdot \sin \theta =1\times 400\times 10^{-9}

\sin \theta =0.28011

\theta =16.26^{\circ}

and \tan \theta =\frac{y}{D}

where y is the position of First maxima corresponding \lambda _1

y_1=D\tan \theta

y_1=0.845 m

calculations for  \lambda _2

d\sin \theta=n\lambda _2

1.428\times 10^{-6}\cdot \sin \theta =1\times 700\times 10^{-9}

\sin \theta '=0.4901

\theta '=29.34^{\circ}

\tan \theta '=\frac{y'}{D}

for n=1

y_1'=D\tan \theta '

y_1'=2.9\times 0.5622=1.63 m

Spectrum Width =y_1'-y_1

=0.785 m

                   

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Answer:

Option C - 39.2 J

Explanation:

We are given that;

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We want to find the work done.

Now, the Formula for work done is given by;

Work = Force × displacement.

In this case, it's force of gravity to lift up the boots, thus;

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∴ Work done = 19.6 × 2

Work done = 39.2 J.

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alina1380 [7]

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4 0
3 years ago
if vector u has lenght 70 and direction 40 degrees, and vector v has length 85 and direction 335 degrees what is the length and
Anastaziya [24]

Answer:

Magnitude of resultant = 131.15

Direction of resultant = 3.97°

Explanation:

||u|| = 70

θ = 40°

\vec{u}_x=||u||cos\theta \\\Rightarrow \vec{u}_x=70cos40=53.62

\vec{u}_y=||u||sin\theta \\\Rightarrow \vec{u}_y=70sin40=44.99

||v|| = 85

θ = 335°

\vec{v}_x=||v||cos\theta \\\Rightarrow \vec{v}_x=85cos335=77.03

\vec{v}_y=||v||sin\theta \\\Rightarrow \vec{v}_y=85sin335=-35.92

Resultant

R=\sqrt{R_x^2+R_y^2}\\\Rightarrow R=\sqrt{(\vec{u}_x+\vec{v}_x)^2+(\vec{u}_y+\vec{v}_y)^2}\\\Rightarrow R =\sqrt{(70cos40+85cos335)^2+(70sin40+85sin335)^2}\\\Rightarrow R =131.15

\theta=tan^{-1}\frac{R_y}{R_x}\\\Rightarrow \theta=tan^{-1}\frac{70sin40+85sin335}{70cos40+85cos335}\\\Rightarrow \theta=tan^{-1}0.069=3.97^{\circ}

Magnitude of resultant = 131.15

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4 0
3 years ago
Tina is driving her sports car down US1, traveling 27m/s. She sees her friend Rita up ahead, waiting to cross the street at the
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Answer:

434 Hz

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According to the Doppler effect, when a source of a wave is moving towards an observer at rest, then the observer will observe an apparent frequency which is higher than the original frequency of the source.

In this situation, Tina is driving towards Rita. Tina is the source of the sound wave (the horn), while RIta is the observer. Since the original frequency of the sound is 400 Hz, Rita will hear a sound with a frequency higher than this value.

The only choice which is higher than 400 Hz is 434 Hz, so this is the frequency that Rita will hear.

3 0
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