Answer:
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Explanation:
Answer:
Net force = 0.0191 N
T=0.00054 N.m
p=99.2 μC.cm
Explanation:
Given that
L= 6.2 cm
q₁= 16μC
q₂=1μC
E= 1174 N/C
We know that
F = q E
F₁ = q₁ E
F₁ = 0.018 N
F₂=q₂ E
F₂=0.0011 N
Net force = F₁+F₂
Net force = 0.0191 N
Torque ,T
T = (F₁-F₂) L/2
T = (0.018 - 0.0011 ) x 0.032
T=0.00054 N.m
Polarization ,p
p= q d
p= 16 x 6.2 μC.cm
p=99.2 μC.cm
Hello,
Your answer would be:
So Dina's maximum velocity on the bottom of the ski slope is v=9.9 m/s.
Answer:
10 N
Explanation:
From the diagram,
Applying the principle of moment,
Sum of clockwise moment = sum of anti clockwise moment.
Assuming: the 10 N is placed on the 5 cm mark, F is placed on the 40 cm mark, The 25 N is placed on the 10 cm mark, the 30 N is placed on the 75 cm mark, and the 40 N is placed on the 80 cm mark.
Therefore,
10(50-5)+F(50-40)+40(80-50) = 30(75-50)+25(50-10)
450+10F+1200 = 750+1000
10F+1650 = 1750
10F = 1750-1650
10F = 100
F = 100/10
F = 10 N
Answer:
q = 1.04×10^-9C
Explanation:
The force on a charge orbiting at the center of the sphere (Fc) is must be equal to the electrostatic force acting on the charge.(Fq)
Fc = Fq
The force that causes a body to bev attracted towards the center of the sphere is the centripetal force.
Centripetal force (Fc) = ma = mv²/r where m is the mass of the body
v is the speed
r is the velocity
The electrostatic force acting on the body is derived according to the Coulomb's law of electrostatic attraction.
Fq = kqe/r²
Where k is the constant
e is the electron orbiting outside the sphere
r is the distance between the charge and the electron
Since fc=fq,
mv²/r = kqe/r²
Making the charge the subject of the formula we have;
mv²r = kqe
q = mv²r/ke
Given the mass of the charge =
8.84×10^-12kg
v = 3.0×10^5
r = 1.0cm = 0.01m
k = 1/4Π£o = 1/4Π×1.67×10^-27
k = 4.77×10^-27
e = 1.6×10^-19C
Substituting the values in the formula given,
q = 8.84×10^-12×(3.0×10^5)²(0.01)/(4.77×10^-27)×1.6×10^-19
q = 1.04×10^-9C
The sphere's charge is 1.04×10^-9