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HACTEHA [7]
3 years ago
10

Are the correct? PLEASE HELP ASAP

Physics
2 answers:
Trava [24]3 years ago
7 0

Energy is the ablity to dow work.

Power is the time rate at which work is done.

independent variable often along x axis, dependent along y axis.

You can set the independent value, from which the dependent follows.


Archy [21]3 years ago
6 0

Energy is the ablity to dow work.

Power is the time rate at which work is done.

independent variable often along x axis, dependent along y axis.

You can set the independent value, from which the dependent follows.


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Two objects were lifted by a machine.One object had a mass of 2 kilograms and was lifted at a speed of 2 m/sec.The other had a m
NikAS [45]

Answer:

While lifting two object the machine needs the different momentum for different mass object.

Explanation:

  • Momentum is the quantity of motion contained in an object. Usually it is measured by the product of mass and velocity.
  • Momentum of first mass = 2 kg × 2 m/sec = 4 kg m/sec
  • Momentum of second mass = 4 kg × 3 m/sec = 12 kg m/sec
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1200 meters is less than 1 kilometer
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<span>1200 meters is less than 1 kilometer 
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8. An unpowered flywheel is slowed by a constant frictional torque. At time t = 0 it has an angular velocity of 200 rad/s. Ten s
allsm [11]

Answer:

a) \omega = 50\,\frac{rad}{s}, b) \omega = 0\,\frac{rad}{s}

Explanation:

The magnitude of torque is a form of moment, that is, a product of force and lever arm (distance), and force is the product of mass and acceleration for rotating systems with constant mass. That is:

\tau = F \cdot r

\tau = m\cdot a \cdot r

\tau = m \cdot \alpha \cdot r^{2}

Where \alpha is the angular acceleration, which is constant as torque is constant. Angular deceleration experimented by the unpowered flywheel is:

\alpha = \frac{170\,\frac{rad}{s} - 200\,\frac{rad}{s} }{10\,s}

\alpha = -3\,\frac{rad}{s^{2}}

Now, angular velocities of the unpowered flywheel at 50 seconds and 100 seconds are, respectively:

a) t = 50 s.

\omega = 200\,\frac{rad}{s} - \left(3\,\frac{rad}{s^{2}} \right) \cdot (50\,s)

\omega = 50\,\frac{rad}{s}

b) t = 100 s.

Given that friction is of reactive nature. Frictional torque works on the unpowered flywheel until angular velocity is reduced to zero, whose instant is:

t = \frac{0\,\frac{rad}{s}-200\,\frac{rad}{s} }{\left(-3\,\frac{rad}{s^{2}} \right)}

t = 66.667\,s

Since t > 66.667\,s, then the angular velocity is equal to zero. Therefore:

\omega = 0\,\frac{rad}{s}

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The proper IUPAC naming convention for the compound symbol 'KI' is
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Proablyly a or c idk 
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A magnetically soft material is placed in a strong magnetic field. What is the most likely outcome?
Svet_ta [14]

D-It will become a temporary magnet because the domains will easily realign.

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