They are helium nuclei, which consist of two protons and two neutrons. The net spin on an alpha particle is zero. They result from large, perilous atoms via a process called alpha decay.
<h3>What is
helium nuclei?</h3>
- The nucleus of the helium atom also understood as the α-particle, includes two protons and two neutrons, encompassed by two electrons.
- Alpha particles are helium nuclei with two protons and two neutrons attached. The development of their high mass and an electrical charge is their inability to infiltrate as deep as other particles such as protons and electrons.
- Particle beams contain α (alpha)-particles, β (beta)-particles, neutron beams, etc. α-particles are helium middles consisting of two protons and two neutrons that have lived removed at high speed, while β-particles are electrons removed from a nucleus. Particle shafts also include neutron beams and proton beams.
To learn more about helium nuclei, refer to:
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Answer:
Explanation 118 = (1/2) * 0.15 * v² 118 = 0.075 * v² v² = 1573.33 m/s ... since KE = m/2*V^2 , then : V = √2KE/m = √20*118/1.5 = 39.67 m//sec ( 142.8 km/h ; 88.75 mph).:
Answer:
442.5 rad
Explanation:
w₀ = initial angular velocity of the disk = 7.0 rad/s
α = Constant angular acceleration = 3.0 rad/s²
t = time period of rotation of the disk = 15 s
θ = angular displacement of the point on the rim
Angular displacement of the point on the rim is given as
θ = w₀ t + (0.5) α t²
inserting the values
θ = (7.0) (15) + (0.5) (3.0) (15)²
θ = 442.5 rad
Answer:
The number of turns in the secondary coil is 4145 turns
Explanation:
Given;
the induced emf on the primary coil, 
= 95 V
the induced emf on the secondary coil, 
= 875 V
the number of turns in the primary coil, 
= 450 turns
the number of turns in the secondary coil, 
= ?
The number of turns in the secondary coil is calculated as;
Therefore, the number of turns in the secondary coil is 4145 turns.
Answer:
v= 14.22 m/s
Explanation:
Given that
u = 12.1 m/s
a=0.35 m/s².
t= 6.07 s
We know v = u +at
v=final velocity
u=initial velocity
t=time
a=acceleration
Now by putting the values in the above equation
v= 12.1 + 0.35 x 6.07 m/s
v= 14.22 m/s
Therefore the final velocity will be 14.22 m/s.
