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mylen [45]
3 years ago
14

The magnetic field at the centre of a toroid is 2.2-mT. If the toroid carries a current of 9.6 A and has 6.000 turns, what is th

e radius of the toroid?
Physics
2 answers:
ziro4ka [17]3 years ago
7 0

Answer:

Radius, r = 0.00523 meters

Explanation:

It is given that,

Magnetic field, B=2\ mT=2.2\times 10^{-3}\ T

Current in the toroid, I = 9.6 A

Number of turns, N = 6

We need to find the radius of the toroid. The magnetic field at the center of the toroid is given by :                  

B=\dfrac{\mu_oNI}{2\pi r}

r=\dfrac{\mu_oNI}{2\pi B}  

r=\dfrac{4\pi \times 10^{-7}\times 6\times 9.6}{2.2\pi \times 2\times 10^{-3}}  

r = 0.00523 m

or

r=5.23\times 10^{-3}\ m

So, the radius of the toroid is 0.00523 meters. Hence, this is the required solution.

Sati [7]3 years ago
6 0

Answer:

The radius of the toroid is 5.23\times10^{-3}\ m.

Explanation:

Given that,

Magnetic field B = 2.2 mT

Current =9.6 A

Number of turns = 6.000

We need to calculate the radius

Using formula of magnetic force

B=\dfrac{\mu_{0}NI}{2\pi r}

r=\dfrac{\mu_{0}NI}{2\pi B}

Put the value int the formula

r=\dfrac{4\pi\times10^{-7}\times9.6\times6.000}{2\pi\times2.2\times10^{-3}}

r=5.23\times10^{-3}\ m

Hence, The radius of the toroid is 5.23\times10^{-3}\ m.

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