Ask question

Ask question

All categories

4 years ago

6

A persons beliefs and general outlook, which Act like filters on the information they receive are called ?

1 answer:

lianna [129]4 years ago

7 0

The correct answer is:

Consideration

<em>Consideration</em> is defined as the act of thinking something carefully, careful thought; meditation; deliberation. Consideration acts like filter on the information a person receives, because it allows them to contemplate the implications of something before acting on it.

You might be interested in

A flat square plate of side 20cm moves over other similar plate with a thin layer of 0.4cm of a liquid between them with force 1

antiseptic1488 [7]

Answer:

$\mu=0.98\ Pa.s$

Explanation:

Given:

dimension of square plate, $l=0.2\ m$

thickness of fluid layer, $dy=0.004\ m$

force on the fluid due to plate, $F=1\ kgw=1\times 9.8=9.8\ N$

velocity of plate, $du=1\ m.s^{-1}$

<u>Using Newton's law of viscosity:</u>

$\tau=\mu.\frac{du}{dy}$ ..........................................(1)

where:

$\tau=$ shear force on the surface on the fluid

$\mu=$ coefficient of (dynamic) viscosity

Now, shear force:

$\tau=\frac{shear\ force}{area}$

$\tau=\frac{9.8}{0.2\times0.2} \ Pa$

Putting respective values in eq.(1)

$\frac{9.8}{0.2\times0.2}=\mu\times\frac{1}{0.004}$

$\mu=0.98\ Pa.s$

7 0

4 years ago

How much force must be applied on a blade of length 4cm and thickness of 0.1mm to exert a pressure of 4000000pa?

Viktor [21]

Answer:

F= 403429 kpa

Explanation:

Pressure is the product of force and area

Mathematically,

P=F*A -------where F is force and A is area.

A= 40 *0.1 = 4mm² -----convert to m²

A= 4e⁻⁶ m²

P= 4000000 pa

F= P/A = 4000000/4e⁻⁶

F= 403428793.493 pa

F= 403429 kpa

7 0

3 years ago

a load of 400 Newton is lifted by a first class lever in which the load is at the distance of 20 cm and the effort is at the dis

Len [333]

Answer:

solution,
Given
load =400N
ld=0.2m
ed=0.6m
effort =150N

Explanation:

efficiency =output work/input work ×100%

l×ld/e×ed×100%

400×0.2/150×0.6×100%

80/90×100%

88.89%ans

7 0

3 years ago

Carbon is allowed to diffuse through a steel plate 15 mm thick. The concentrations of carbon at the two faces are 0.65 and 0.30

beks73 [17]

Answer:

T=575.16K

Explanation:

To solve the problem we proceed to use the 1 law of diffusion of flow,

Here,

$J=-D\frac{\Delta C}{\Delta x}$

$\Delta C$ is the rate in concentration

$\Delta x$ is the rate in thickness

D is the diffusion coefficient, where,

$D= D_0 exp(\frac{Q_d}{RT})$

Replacing D in the first law,

$J=-(D_0 exp(\frac{-Q_D}{RT}))\frac{\Delta }{\Delta x}$

clearing T,

$T=\frac{Q_d}{R*ln(\frac{J*\Delta x}{D_0*\Delta C})}$

Replacing our values

$T=-\frac{80000}{8.31*ln(\frac{(6.2*10^{-7})(-15*10^{-3})}{(1.43*10^{-9})(0.65-0.30)})}$

$T=-\frac{80000}{-138.09}$

$T=575.16K$

4 0

4 years ago

When we perform an experiment we

Verizon [17]

Write a:
● Hypothesis
●Procedures
●Materials
●Data Table
●Conclusion
●Variables (Independent and dependent)
●Bibliography

4 0

3 years ago