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Assoli18 [71]
3 years ago
15

A black, absorbing piece of card board of area A = 2.0 cm2 absorbs light with intensity 18 W/m2. What is the force exerted on th

e cardboard by the light? b) 9.33x10-12 N e) 1.67x10-11 N a) 6.67x10-12 N d) 1.20x10-11 N c) 1.15x10-12 N
Physics
1 answer:
aleksklad [387]3 years ago
5 0

Answer:

The force exerted on the cardboard by the light is 1.2\times 10^{-11}\ N

Explanation:

It is given that,

Area of the cardboard, A=2\ cm^2=0.0002\ m^2

Intensity of absorbance, I=18\ W/m^2

Radiation pressure in case of absorption is given by :

P=\dfrac{I}{c}...........(1)

c is the speed of light

The relation between force and pressure is given by :

P=\dfrac{F}{A}.......(2)

From equation (1) and (2):

F=\dfrac{IA}{c}

F=\dfrac{18\ W/m^2\times 0.0002\ m^2}{3\times 10^8\ m/s}

F=1.2\times 10^{-11}\ N

So, the force exerted on the cardboard by the light is 1.2\times 10^{-11}\ N. Hence, this is the required solution.

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