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scZoUnD [109]
2 years ago
13

An object is dropped from rest from a 70.6 m tower. Air resistance is negligible. After 0.32 seconds, what is magnitude and dire

ction of its acceleration?
Physics
1 answer:
dem82 [27]2 years ago
7 0

Answer:

<em>1,378.9ms²</em>

Explanation:

Given the following

Distance S = 70.6m

Time t = 0.32secs

Initial velocity = 0m/s

Required

Acceleration

Using the equation of motion

S = ut+1/2at²

Substitute

70.6 = 0+1/2a(0.32)²

70.6 = 0.0512a

a = 70.6/0.0512

a = 1,378.9

<em>Hence the acceleration is 1,378.9ms²</em>

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Explanation:

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3 years ago
In an inelastic collision a 2.5 kg ball moving at 7.5 m/s is caught by a 70kg man while the man is standing on ice. What is the
MrRa [10]

The velocity of the ball and the man is 0.259 m/s

Explanation:

We can solve this problem by using the law of conservation of momentum. In fact, in an isolated system, the total momentum before and after the collision must be conserved. Therefore, for the ball-man system, we can write:

p_i = p_f\\m_1 u_1 + m_2 u_2 = (m_1+m_2)v

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m_1 = 2.5 kg is the mass of the ball

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v=\frac{m_1 u_1}{m_1+m_2}=\frac{(2.5)(7.5)}{2.5+70}=0.259 m/s

So, the man and the ball slides on the ice at 0.259 m/s.

Learn more about momentum:

brainly.com/question/7973509

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3 0
2 years ago
What are the 3 basic parts of an atom and what are their charges?
kotegsom [21]

Answer:

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