Answer:
The magnitude of force is 1593.4N
Explanation:
The sum of the horizontal components of the friction and the normal force will be equal to the centripetal force on the car. This can be represented as
fcostheta + Nsintheta = mv^2/r
Where F = force of friction
Theta = angle of banking
N = normal force
m = mass of car
v = velocity of car
r = radius of curve
The car has no motion in the vertical direction so the sum of forces = 0
The vertical component of the normal force acts upwards whereas the weight of the car and the vertical component friction acts downwards.
Taking the upward direction to be positive,rewrite the equation above to get:
Ncos thetha = mg - fsintheta =0
Ncistheta = mg + fain theta
N = mg/cos theta + sintheta/ costheta
fcostheta +[mg/costheta + ftan theta] sin theta = mv^2/r
Substituting gives:
f = (1/(costheta + tanthetasintheta) + mgtantheta = mv^2/r - mgtantheta)
Substituting given values into the above equation
f = 1/(cos25 + tan 25 )(sin25)[ 600×30/120 - (600×9.81)tan
f = 1593.4N25
.