I believe the answer should be D
Answer:
28.2 m/s
Explanation:
The range of a projectile launched from the ground is given by:

where
v is the initial speed
g = 9.8 m/s^2 is the acceleration of gravity
is the angle at which the projectile is thrown
In this problem we have
d = 81.1 m is the range
is the angle
Solving for v, we find the speed of the projectile:

Answer:

Explanation:
Given that:
mass of object A, 
mass of object B, 
speed of object A, 
So, according to the conservation of momentum, the momentum before collision is equal to the momentum after conservation.




I believe the correct answer is expansion.
The object rises to a height of 20.4 m. So option C is correct.
Explanation:
initial velocity= Vi=20 m/s
final velocity at the top= Vf=0
acceleration= g=-9.8 m/s²
Vf²=Vi²+2gh
0= (20)²+2 (-9.8)h
-200=-9.8h
h=200/9.8
h=20.4 m
Thus the object rises to a height of 20.4 m