Answer:
The current is 
Explanation:
From the question we are told that
The radius is 
The current density is 
The distance we are considering is 
Generally current density is mathematically represented as

Where A is the cross-sectional area represented as

=> 
=> 
Now the change in current per unit length is mathematically evaluated as

Now to obtain the current (in A) through the inner section of the wire from the center to r = 0.5R we integrate dI from the 0 (center) to point 0.5R as follows


![I = 2\pi *(9.0*10^{6}) [\frac{r^4}{4} ] | \left 0.001585} \atop 0}} \right.](https://tex.z-dn.net/?f=I%20%20%3D%202%5Cpi%20%2A%289.0%2A10%5E%7B6%7D%29%20%5B%5Cfrac%7Br%5E4%7D%7B4%7D%20%5D%20%20%7C%20%5Cleft%20%20%20%200.001585%7D%20%5Catop%200%7D%7D%20%5Cright.)
![I = 2\pi *(9.0*10^{6}) [ \frac{0.001585^4}{4} ]](https://tex.z-dn.net/?f=I%20%20%3D%202%5Cpi%20%2A%289.0%2A10%5E%7B6%7D%29%20%5B%20%5Cfrac%7B0.001585%5E4%7D%7B4%7D%20%5D)
substituting values
![I = 2 * 3.142 * 9.00 *10^6 * [ \frac{0.001585^4}{4} ]](https://tex.z-dn.net/?f=I%20%20%3D%202%20%2A%20%203.142%20%20%2A%20%209.00%20%2A10%5E6%20%2A%20%20%20%5B%20%5Cfrac%7B0.001585%5E4%7D%7B4%7D%20%5D)

Power is the rate of doing work.
Its unit is joules/second.
That unit is used so often that a new word was adopted for it.
1 joule/sec = 1 watt
Answer:
According to Archimedes principle the upthrust on the body is equal to the weight of the water displaced by the body. ... Here, the mass would be the net difference in the weight of the object.
From the information given,
diameter of ornament = 8
radius = diameter/2 = 8/2
radius of curvature, r = 4
Recall,
focal length, f = radius of curvature/2 = 4/2
f = 2
Recall,
magnification = image d