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xxTIMURxx [149]
3 years ago
8

Earth's tides are primarily caused by _____.

Physics
2 answers:
Fiesta28 [93]3 years ago
8 0
B.) The moon 

There you go.
Alecsey [184]3 years ago
8 0

Answer:

Tides are caused by moon.

Explanation:

The tides are primarily formed by the gravitational attraction of moon on the surface of oceans.

At the time of full moon and new moon, the tides are higher because at that time, there is a gravitational pull of sun also which adds up with the gravitational pull of moon.

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Which statement is a hypothesis?
shusha [124]
I believe the answer should be D
8 0
3 years ago
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The record distance in the sport of throwing cowpats is 81.1 m. This record toss was set by Steve Urner of the United States in
N76 [4]

Answer:

28.2 m/s

Explanation:

The range of a projectile launched from the ground is given by:

d=\frac{v^2}{g}sin 2\theta

where

v is the initial speed

g = 9.8 m/s^2 is the acceleration of gravity

\theta is the angle at which the projectile is thrown

In this problem we have

d = 81.1 m is the range

\theta=45^{\circ} is the angle

Solving for v, we find the speed of the projectile:

v=\sqrt{\frac{dg}{sin 2 \theta}}=\sqrt{\frac{(81.1 m)(9.8 m/s^2)}{sin (2\cdot 45^{\circ})}}=28.2 m/s

7 0
3 years ago
Object A of mass M is moving east at speed v. It collides with object B of mass 2M that was initially at rest. The motion of the
Firlakuza [10]

Answer:

v_B=\frac{v}{3}

Explanation:

Given that:

mass of object A, m_A=M

mass of object B, m_B=2M

speed of object A, v_A=v

So, according to the conservation of momentum, the momentum before collision is equal to the momentum after conservation.

m_A.v+m_B\times 0=m_A\times v_A +m_B\times v_B

M\times v+0 = M\times \frac{v}{3}+2M\times v_B

2M\times v_B= \frac{2M\times v}{3}

v_B=\frac{v}{3}

3 0
3 years ago
The increase in volume of a material due to a temerature increased is called?
kakasveta [241]
I believe the correct answer is expansion.
7 0
3 years ago
An object is thrown directly up (positive direction) with a velocity (vo) of 20.0 m/s and do= 0. How high does it rise (v = 0 cm
stepan [7]

The object rises to a height of 20.4 m. So option C is correct.

Explanation:

initial velocity= Vi=20 m/s

final velocity at the top= Vf=0

acceleration= g=-9.8 m/s²

Vf²=Vi²+2gh

0= (20)²+2 (-9.8)h

-200=-9.8h

h=200/9.8

h=20.4 m

Thus the object rises to a height of 20.4 m

7 0
3 years ago
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