The answer is c. ![\frac{46}{9}](https://tex.z-dn.net/?f=%20%5Cfrac%7B46%7D%7B9%7D%20%20)
a.
(2.2≠5.11) (2.2 is not equal to 5.11)
b.
or 0.625 (0.625≠5.11) (0.625 is not equal to 5.11)
c.
(5.11=5.11) (5.11 is equal to 5.11)
Therefore c is the answer
Answer:
Maximization and Minimization Problems on Feasible Regions
Step-by-step explanation:
go to that yt vid
Answer:
The range of this function is {-13, -1, 15}.
Step-by-step explanation:
Evaluate f(x) = 4x - 1 at {-3, 0, 4}:
f(-3) = -13
f(0) = -1
f(4) = 15
The range of this function is {-13, -1, 15}.
Answer:
![\sqrt{118}\approx 10.86](https://tex.z-dn.net/?f=%5Csqrt%7B118%7D%5Capprox%2010.86)
![\sqrt{319}\approx 17.86](https://tex.z-dn.net/?f=%5Csqrt%7B319%7D%5Capprox%2017.86)
Step-by-step explanation:
Consider the provided number.
We need to find the approximate value of
to the nearest hundredth.
First find two perfect squares that the irrational number falls between.
![100](https://tex.z-dn.net/?f=100%3C118%3C121)
118 is lying between 100 and 121, therefore the square root value of 118 will be somewhere between 10 and 11.
![\sqrt{100}](https://tex.z-dn.net/?f=%5Csqrt%7B100%7D%3C%5Csqrt%7B118%7D%3C%5Csqrt%7B121%7D)
![10](https://tex.z-dn.net/?f=10%3C%5Csqrt%7B118%7D%3C11)
118 is closer to 121 as compare to 100.
Therefore, ![\sqrt{118}\approx 10.86](https://tex.z-dn.net/?f=%5Csqrt%7B118%7D%5Capprox%2010.86)
Consider the number ![\sqrt{319}](https://tex.z-dn.net/?f=%5Csqrt%7B319%7D)
First find two perfect squares that the irrational number falls between.
![289](https://tex.z-dn.net/?f=289%3C319%3C324)
319 is lying between 289 and 324, therefore the square root value of 319 will be somewhere between 17 and 18.
![\sqrt{289}](https://tex.z-dn.net/?f=%5Csqrt%7B289%7D%3C%5Csqrt%7B319%7D%3C%5Csqrt%7B324%7D)
![17](https://tex.z-dn.net/?f=17%3C%5Csqrt%7B319%7D%3C18)
319 is closer to 324 as compare to 289.
Therefore, ![\sqrt{319}\approx 17.86](https://tex.z-dn.net/?f=%5Csqrt%7B319%7D%5Capprox%2017.86)