Select the graph for the solution of the open sentence. Click until the correct graph appears.

Rectangle A is a scale drawing of Rectangle B and has 25% of its area. If rectangle A has side lengths of 4 cm and 5 cm , what a

SpyIntel [72]

Answer:

8 cm and 10 cm

Step-by-step explanation:

Hello, <em> </em>I can help you with this.

Step 1

According to the question there are two rectangles A and B,

Rectangle A is a scale drawing of Rectangle B and has 25% of its area

in other words

$Area_{A}=0.25*Area_{B} (Equation\ 1)\\$

Step 2

Let

Rectangle A

length (1)= 4 cm

length (2)= 5 cm

$Area_{A}=4\ cm * 5\ cm\\Area_{A}=20\ cm^{2}$

put this value into equation 1

$Area_{A}=0.25*Area_{B} (Equation\ 1)\\\\20\ cm^{2} =0.25*Area_{B} \\divide\ each\ side\ by\ 0.25\\\frac{20\ cm^{2} }{0.25}=\frac{0.25}{0.25}*Area_{B}\\ Area_{B}=80\ cm^{2}$

Now, we know the area of rectangle B, to know its length we need to formule other equation

Step 3

$Area_{B}=80\ cm^{2}\\length (1B)*length (2B)=80\ cm^{2} (equation\ 2)\\$

the ratio between the lengths must be constant, so the ratio of A must be equal to ratio in B, then

$\frac{length(1A)}{length(2A)}=\frac{length(1B)}{length(2B)} \\\\\\frac{4}{5}= \frac{length(1B)}{length(2B)}\\0.8=\frac{length(1B)}{length(2B)}\\length(1B)=0.8*length(2B) (Equation 3)$

Step three

using Eq 1 and Eq 2 find the lengths

put the value of length(1B) into equation (2)

$length (1B)*length (2B)=80\ cm^{2} (equation\ 2)\\\(0.8*length(2B)) (*length (2B)=80\ cm^{2} \\\\0.8*(length (2B))^{2} =80\ cm^{2}\\(length (2B))^{2} =\frac{80\ cm^{2}}{0.8} \\(length (2B))^{2}=100\\\sqrt{(length (2B))^{2}}=\sqrt{100\ cm^{2}} \\ length (2B)=10\ cm$

Now, put the value of length(2B) into equation 3 to know length (1B)

$length(1B)=0.8*length(2B)\\length(1B)=0.8*10\ cm\\length(1B)=8 cm$

I really hope this helps you, have a great day.

6 0

3 years ago

The diagonals of a rhombus are

lisabon 2012 [21]

Answer:

B

Step-by-step explanation:

5 0

2 years ago

Here is a rectangle ABCD. The length of the rectangle is increased by 10%. The width of the rectangle is increased by 5%. Find t

sladkih [1.3K]

Answer: Width would become 21 and length would become 33. Original perimeter is 100, increased perimeter is 108 which is a 7.69% increase

6 0

2 years ago

How many pennies could you have if: When you Break de Pennies into groups of 2, you have 1 penny left over, AND when you break t

MariettaO [177]

Answer:

The answer is 31 pennies

Step-by-step explanation:

we have to find a number that gives a remainder of 1 when divided by both 2, 3 and 5.

The easiest way to do this is to list the factors of 5, add 1 to it, and test them until we find the one with a remainder of 1 by all three divisors. This is done as follows:

1) factor: 5 (+1) = 6

6 ÷ 2 = 3 remainder 0

6 ÷ 3 = 2 remainder 0

since there is a remainder of 0, when divided by 3, 6 is wrong

2) factor; 10 (+1) = 11

11 ÷ 3 = 3 remainder 2 ( 11 is not the correct answer

3) factor : 15 (+1) = 16

16 ÷ 2 = 8 remainder 0 ( 16 is not the correct answer

4) factor : 20(+1) = 21

21 ÷ 3 = 7 remainder 0 ( 21 is wrong)

5) factor : 25(+1) = 26

26 ÷ 2 = 13 remainder 0 ( 26 is wrong)

6) factor : 30(+1) = 31

31 ÷ 2 = 15 Remainder 1

31 ÷ 3 = 10 Remainder 1

31 ÷ 5 = 6 Remainder 1

since all three divisors give a remainder of 1, the correct answer is 31

Therefore you have 31 pwnnies

6 0

2 years ago

Suppose that the current equilibrium price of silver is $34 per ounce. If silver is produced under conditions of perfect competi

Bond [772]

Answer:

b. is $34 per ounce

Step-by-step explanation:

If the production cost were less, a competitor would drive the price down. If the production cost were more, the supplier would go out of business.

Since we're at equilibrium, the production cost must be equal to $34 per ounce.

6 0

3 years ago