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kkurt [141]
3 years ago
14

Phosgene is formed from carbon monoxide and chlorine. At 611 oC, Kc is approximately 16.5 M-1 or L/mol. Calculate Kp (in atm-1)

at this temperature.
Chemistry
1 answer:
defon3 years ago
5 0

Answer:

Kp is 0.228/atm

Explanation:

This is the reaction:

CO + Cl<u>₂</u> → CCl₂O

1 mol of carbon monoxide and 1 mol of chlorine produce 1 mol of phosgene.

Formula for Kp which derivates from Kc is:

Kp = Kc (R.T)ⁿᵇ ⁻ ⁿᵃ

Δп = nb (moles in the products) - nₐ(moles in the reactants)

Δп = 1 - 2 = -1

T is T° in K → T°C + 273 = 611°C +273 = 884K

R → Universal constant gas → 0.082 L.atm/mol.K

We replace the data: Kp = 16.5 L/mol (0.082 . 884K)⁻¹ → 0.228/atm

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Solid mixture contains MgCl2 and NaCl. When 0.5000 g of this solid is dissolved in enough water to form 1.000 L of solution, the
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Answer:

83,40 (w/w) %

Explanation:

The osmotic pressure (π) is defined as:

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iM = 0,01607mol/L

It is possible to write:

<em>3x+2y = 0,01607mol/L </em><em>(1)</em>

Where x are moles of MgCl₂ and y moles of NaCl.

<em>-M = moles of each compund because M is molarity (moles/L) and there is 1,000L-</em>

Knowing molar mass of MgCl₂ is 95,2 g/mol and for NaCl is 58,44g/mol:

<em>x×95,211 + y×58,44 = 0,5000g </em><em>(2)</em>

Replacing (2) in (1):

3x+2(0,0086 - 1,629x) = 0,01607mol/L

-0,258x = -0,00113

<em>x = 0,004380 moles of MgCl₂</em>

In grams:

0,004380 moles of MgCl₂×(95,211g/mol) = 0,417g of MgCl₂

Mass percent is:

(0,4170g of MgCl₂/0,5000g of solid) ×100 = <em>83,40 (w/w) %</em>

I hope it helps!

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