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Tju [1.3M]
3 years ago
5

What is energy, what is power, and how are they related?

Chemistry
2 answers:
Romashka [77]3 years ago
7 0

Answer:

Energy and power are closely related but are not the same physical quantity. Energy is the ability to cause change; power is the rate energy is moved, or used. Energy main article Energy is the ability to create a change, for example, creating motion. Tasks (like lifting a box) require an amount of energy to complete.

Explanation:

koban [17]3 years ago
7 0

Answer:

Energy is a force conducted by machinery like PSi ( pressured air )  or naturally aspirated such as electricity or water mills

Explanation:

Power is the amount of energy transferred or converted per unit time.

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Think critically explain how biotic change in an ecosystem that has flooded?
Scorpion4ik [409]

Answer:

Organisms that do not live in water would either have to adapt, or they would die. Other water organisms might move into the ecosystem. Diseases that are waterborne might make a surge.

Explanation:

8 0
3 years ago
2. Arnie is going to dissolve 2.65g of zinc using 6.0M hydrochloric acid. A) what volume of the acid will he need to dissolve al
fenix001 [56]

Answer:

Explanation:

Zn + 2HCl = ZnCl₂ + H₂

A ) mole of Zn = 2.65 / 65

= .04 mol

mole of HCl required = .04 x 2 mol

.08 mol

If v be the volume required

v x 6 = .08

v = .0133 liter

= 13.3 cc

B )

volume of gas at NTP :

moles of gas  obtained = .04 moles

= 22.4 x .04 liter

= .896 liter

we have to find this volume at given temperature and pressure

\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}

\frac{760\times.896}{273} =\frac{628\times V_2}{296}

V_2 = 1.175 liter.

C )

.04 mole of zinc chloride will be produced

mol weight of zinc chloride

= 65 + 35.5 x 2

= 136 gm

.04 mole = 136 x .04

= 5.44 gm

5 0
3 years ago
What is the electrode in the center of the most common dry cell made of?
Svetllana [295]
A common dry-cell battery is the zinc-carbon battery, which uses a cell that is sometimes called the Leclanché cell. The cell is made up of an outer zinc container, which acts as the anode.
8 0
3 years ago
Read 2 more answers
What is the mole of 125 mg of Na? How many Na atoms?
Crank
(125 mg Na) x (1 g/1000mg) x (1 mol of Na/22.99 g) = 5.43 E -3 mols of Na

5.43 E -3 mols x 6.022 E 23 = 3.27 E 21 Na atoms
7 0
3 years ago
The formation of nitryl fluoride, 2no2(g)+f2(g)⇌2no2f(g) is first order in no2 and first order in f2. if the concentration of no
ra1l [238]
The reaction is:

2 NO₂ (g) + F₂ (g) ⇆  2 NO₂F (g)

The stoichiometric coefficients of the substances balance out each other to obey the Law of Definite Proportions. Now, you have to note that determining the reaction rate expression is specific to a certain type of reaction. So, this are determined empirically through doing experiments. But in chemical reaction engineering, to make things simple, you assume that the reaction is elementary. This means that the order of a reaction with respect to a certain substance follows their individual stoichiometric coefficients. What I'm saying is, the stoichiometric coefficients are the basis of our reaction rate orders. For this reaction, the rate order is 2 for NO₂, 1 for F₂ and 2 for NO₂F. When the forward and reverse reactions are in equilibrium, then it applies that:

Reaction rate of disappearance of reactants = Reaction rate of formation of products.

Therefore, we can have two reaction rate constants for this. But since the conditions manipulated are the reactant side, let's find the expression for reaction rate of disappearance of reactants.

-r = k[NO₂]²[F₂]

The negative sign before r signifies the rate of disappearance. If it were in terms of the product, that would have been positive. The term k denotes for the reaction rate constant. That is also empirical. As you can notice the stoichiometric coefficients are exponents of the concentrations of the reactants. Let's say initially, there are 1 M of NO₂ and 1 M of F₂. Then,

-r = k(1)²(1)
-r = k

Now, if we change 1 M of NO₂ by increasing it to its half, it would now be 1.5 M NO₂. Then, if we quadruple the concentration of F₂, that would be 4 M F₂. Substituting the values:

-r = k(1.5)²(4)
-r = 9k

So, as you can see the reaction rate increase by a factor of 9.
4 0
4 years ago
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