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3 years ago

13

Give the location of the elements found in the periodic table which have the same valence electrons. all members in group VIII o

nly all members within any group all members within any period all the nonmetals

2 answers:

Gekata [30.6K]3 years ago

7 0

Valence is the same in every family... except for transition metals, it goes from 1-8

dk if that helped

Ghella [55]3 years ago

3 0

the correct answer is "all members within any period"

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How many fluorine atoms are present in 5.71 g of C2F4? Please explain in steps!

Leya [2.2K]

Molar mass of C= 12g/mol
2C= 2*12g/mol= 24g/mol
Molar Mass of F=19g/mol
4F= 4*19g/mol= 76g/mol
Total molar mass of C2F4 = (24g/mol+76g/mol)= 100g/mol

Now you need to find the moles of Fluorine
Moles= Mass/molar mass
Moles of Fluorine = 5.71g/100g/mol=0.0571mol of Fluorine

To find the number of atoms you multiply moles by Avogadro's number( $6.022*10 ^{23}$ )

So the number of Fluorine atoms= 0.0571* 6.022x10^23= 3.44x10^22 atoms or $3.44 *10^{22}$ atoms

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3 years ago

How do bubbles support the atomic theory?

Tpy6a [65]

A. The bubbles are lighter than air.
B. There is matter that cannot be seen inside the bubbles.
C. The bubbles will burst before long.
D. The bubbles cannot be broken into smaller pieces.

3 0

3 years ago

Which describes a chemical property of<br> copper

irga5000 [103]

Answer:

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8 0

3 years ago

Read 2 more answers

Vinegar is an aqueous solution of acetic acid, ch3cooh. a 5.00 ml sample of a particular vinegar requires 26.90 ml of 0.175 m na

Fed [463]

The molarity of acetic acid in the vinegar is 0.94 M

<u><em> calculation</em></u>

Step 1: write the balanced equation between CH3COOH + NaOH

that is CH3COOH + NaOH → CH3COONa + H2O

step 2 : find the moles of NaOH

moles =molarity x volume in L

volume in liters = 26.90/1000=0.0269 l

moles = 0.175 mol /L x 0.0269 L =0.0047 moles of NaOH

Step 3: use the mole ratio to find moles of CH3COOH

that is the mole ratio of CH3COOH: NaOH is 1:1 therefore the moles of CH3COOH is =0.0047 moles

Step 4: find the molarity of CH3COOH

molarity = moles/volume in liters

volume in liter = 5.00/1000 =0.005 l

molarity is therefore=0.0047 moles/ 0.005 l = 0.94 M

4 0

4 years ago

If a sample contains 70.0 % of the R enantiomer and 30.0 % of the S enantiomer, what is the enantiomeric excess of the mixture?

NeTakaya

Answer:

the enantiomeric excess of the mixture is 40%

Explanation:

The computation of the enantiomeric excess of the mixture is shown below:

As we know that

$= |\frac{R - S}{R + S} |\times 100\\\\= |\frac{70 - 30}{70 + 30}| \times 100\\\\= 40\%$

Hence, the enantiomeric excess of the mixture is 40%

3 0

3 years ago