Answer:
B : 0.133 M
Explanation:
moles Li3N3 = 0.4 mol Li x (2 moles Li3N/6 moles Li) = 0.133 M
Answer:
It's IF5. ................
Organisms are living things. Us humans are also living things, so we are helpful and harmful to other organisms. For example: we can help another human being with something, or we can help a plant/tree grow if we water it. In return, they also help us by providing us with oxygen. however, we can also be harmful to each other and the environment, for example: we can't hurt each other, or plant or animals by killing them or we can hurt insects by stepping on them. Therefore, organisms are helpful and harmful to each other.
Answer:
n = 3
l = 1
ml = +1
ms = +1/2
Es paramagnético
Explanation:
Siguiendo las reglas de llenado de orbitales, los 17 electrones del cloro se llenan así:
1S = <u>⇅</u>
2S = <u>⇅</u>
2P = <u>⇅</u> <u>⇅</u> <u>⇅</u>
3S = <u>⇅</u>
3P = <u>⇅</u> <u>⇅</u> <u>↑</u>
<u />
El número cuántico principal n, es el nivel energético donde se encuentra este electrón:
n = 3 (Porque está en el orbital 3P
El número cuántico secundario, l, para el orbital 3P es = 1:
l = 1
El número cuántico magnético, ml, es determinado por la posición del electrón. Como está en el tercer orbital 3P:
ml = +1
Y el número cuántico de spin, ms (↑ = +1/2; ↓ = -1/2)=
ms = +1/2
Dado que el último electrón se encuentra desapareado, el cloro es paramagnético dado que el espín de el último electrón no tiene su electrón complementario haciendo que este compuesto pueda interactuar con un campo magnético.
Answer:
C₂H₃Cl₃O₂
Explanation:
Given parameters:
Percentage composition:
14.52% C
1.83% H
64.30% Cl
19.35% O
Molar mass = 165.4 g/mo
Unknown:
Empirical formula = ?
Solution:
The empirical formula of a compound is the simplest formula of a compound. To solve this problem, let us follow the process below:
C H Cl O
%composition 14.52 1.83 64.3 19.35
Molar mass 12 1 17 16
number of
moles 14.52/12 1.83/1 64.3/3.5 19.35/16
1.21 1.83 1.81 1.21
Divide by
the smallest 1.21/1.21 1.83/1.21 1.81/1.21 1.21/1.21
1 1.51 1.51 1
multiply
by 2 2 3 3 2
Empirical formula C₂H₃Cl₃O₂
