It is given that, a driver can probably survive an acceleration of 50 g that lasts for less than 30 ms, but in a crash with a 50 g acceleration lasting longer than 30 ms, a driver is unlikely to survive.

Let v is the highest speed that the car could have had such that the driver survived. Using a = -50 g and t = 30 ms

Using first equation of kinematics as :

$v=u+at$

In case of crash the final speed of the driver is, v = 0

$0=u+at$

$-u=at$

$-u=-50\times 9.8\times 30\times 10^{-3}$

u = 14.7 m/s

So, the highest speed that the car could have had such that the driver survived is 14.7 m/s. Hence, this is the required solution.

8 0

3 years ago

A chemist wade out 5.96 grams of barium calculate the number of moles of barium she weighed out

PilotLPTM [1.2K]

Answer:

0.04 mol

Explanation:

Given data:

Mass of barium = 5.96 g

Moles of barium = ?

Solution:

Formula:

Number of moles = mass/molar mass

Molar mass of barium = 5.96 g/ 137.33 g/mol

Number of moles = 0.04 mol

Thus the number of moles of barium in 5.96 g are 0.04 moles. The chemist weight out the 0.04 moles .

7 0

4 years ago

6. What is the molarity of 175 mL of solution containing 2.18 grams of NazS04-10H2O?

Ymorist [56]

Answer:

$Molarity\,\,of\,\,the\,\,solution\,\,is\,\,S=0.039M$

Explanation:

$W=2.18 g\\M=322g\\V=175mL=0.175L\\\\S=\frac{W}{MV} \\=>S=\frac{2.18}{322*0.175} \\So,S=0.039M$

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8 0

3 years ago

The percent yield of a reaction in 2 points which 52 grams of a reactant is expected to yield 30 grams of product is 25%. What i

bagirrra123 [75]

Answer:

idk

Explanation:

dong know

6 0

3 years ago