<span>Between the generating station and consumer, electric power may flow through several substations at different voltage levels. that it </span>
Electrical force between the two charges is (attractive)
Explanation:
The magnitude of the electrostatic force between two charged particles is given by Coulomb's law:
where:
is the Coulomb's constant
are the charges of the two particles
r is the separation between the two particles
In this problem, we have:
is the charge of the first particle
is the charge of the second particle
r = 3 m is the separation between them
Substituting into the formula, we find the force:
And the negative sign means the force is attractive (the electric force between two charges with opposite sign is attractive)
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Thats is instantaneous bc it’s in the moment
Answer:
v = 23.66 m/s
Explanation:
recall that one of the equations of motion may be expressed:
v² = u² + 2as,
Where
v = final velocity (we are asked to find this)
u = initial velocity = 0 m/s since we are told that it starts from rest
a = acceleration = 0.56m/s²
s = distance traveled = given as 500m
Simply substitute the known values into the equation:
v² = u² + 2as
v² = 0 + 2(0.56)(500)
v² = 560
v = √560
v = 23.66 m/s