Answer:
6 second
Explanation:
initial velocity of ball, u = 60 m/s
g = 10 m/s^2
Let the ball takes time t to reach at the maximum height
We know that at maximum height, the velocity of ball is zero.
v = 0 m/s
Use first equation of motion
v = u + gt
0 = 60 - 10 x t
t = 6 second
Thus, the ball takes 6 second to reach to maximum height.
False.
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Answer:
636.4 J
Explanation:
The potential energy between one of the charges at the corner of the square and the fifth identical charge is U = kq²/r where q = charge = +50 × 10⁻⁶ C and r = distance from center of square. = √2 m (since the midpoint of the sides = 1 m, so the distance from the charge at the corner to the center is thus √(1² + 1²) = √2)
Since we have four charges, the additional potential energy to move the charge to the centre of the square is U' = 4U = 4kq²/r
U' = 4kq²/r
= 4 × 9 × 10⁹ Nm²/C² (+50 × 10⁻⁶ C)²/√2 m
= 900 Nm²/√2 m
= 636.4 J
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