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Andre45 [30]
4 years ago
15

A small circular loop of 5 mm radius is placed 1 m away from a 60-Hz power line. The voltage induced on this loop is measured at

0.6 µV. What is the current on the power line

Physics
1 answer:
marin [14]4 years ago
5 0

Answer:

i = 101.4A

Explanation:

The steps to the solution can be found in the attachment below.

We have been given the frequency f = 60Hz. From this we can calculate the angular frequency of the power line.

It is assumed that sinwt = –1 in order to calculate the time varying current. Although the magnitude of the current is large, consideration should also be given to the distance between the coil and the power line. The induced emf is small considering the area of the coil which is 7.85×10-⁵m².

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When the temperature of an ideal gas is increased, the pressure also ________
kherson [118]
<h2>Answer: increases  </h2><h2 />

Explanation:  

The expression for an Ideal Gas is:  

P.V=n.R.T  

Where:  

P is the pressure of the gas  

V is the volume of the gas  

n the number of moles of gas  

R is the gas constant  

T is the absolute temperature of the gas  

As we can see, there is a <u>direct proportional relation between the temperature and the pressure</u>, which means that if the temperature increases the pressure of the gas increases as well.

However, it is important to note this is fulfilled if and only<u> if the volume of the container where the ideal gas is, remains constant.</u>

6 0
3 years ago
On the moon, which objects would fall with the same acceleration?
I am Lyosha [343]
On a planet/celestial body with gravity, the acceleration of gravity is the same for everything.  Therefore, all three options are correct.

Hope this helps!
6 0
4 years ago
Read 2 more answers
• Usain Bolt can run at 10 m/s. If he runs for about 20 seconds, how far around the race track did he go?
yanalaym [24]

Answer:

200metters

Explanation:

because in one second hes going 10 metter in 20 second he will go 20×10=200

4 0
3 years ago
un proyectil parte de su reposo con una aceleracion de 9.5 m/s si su aceleracion es constante determine en que tiempo va ha alca
IRISSAK [1]

Responder:

Explicación:

Usando una de las ecuaciones de movimiento expresadas como;

v = u + en donde;

v es la velocidad final del objeto

u es la velocidad inicial del objeto

a es la aceleración

t es el tiempo que toma

Parámetros dados

v = 150 m / s

u = 0 m / s

a = 9,5 m / s²

Necesario

tiempo tomado

Al sustituir los parámetros dados en la fórmula

150 = 0 + 9.5t

9,5 t = 150

Dividiendo ambos lados por 9.5

9,5 t / 9,5 = 150 / 9,5

t = 15,79 segundos

Por lo tanto, el tiempo que alcanzará una velocidad de 150 m / s es de 15,79 segundos.

6 0
3 years ago
A 143-g baseball is flying through the air with a speed of 180 km/hr just after it is hit by a bat. If its velocity is at an ang
Svetllana [295]

To solve the problem it is necessary to apply the concepts related to the conservation of linear Moment, that is to say

P=mv

Where,

m = Mass

v = Velocity

P = Linear momentum

For the given data we have to:

v_1 = 180\frac{km}{h}(\frac{1h}{3600s})(\frac{1000m}{1km})

v_1 = 50m/s

The components of this force would be given by,

v_z = 50*sin37 = 30.09m/s

v_{x,y} = 50*cos37=39.93m/s \rightarrwAccording to the definition given at the end of the problem, this component corresponds to that expressed for x and y.

Applying the previous equation we have,

\vec{P} = m(39.93cos\theta \hat{i}+39.93sin\theta \hat{j}-30.09\hat{k})

<em>Note: The component at this direction must also decomposed</em>

The mass is 143g=0.143kg, then:

\vec{P} = (0.143)(39.93cos(22)\hat{i}+39.93sin(22) \hat{j}-30.09\hat{k})

Therefore the final vector is:

\vec{P} = 5.29\hat{i}+2.138\hat{j}-4.29\hat{k})

5 0
3 years ago
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