A small circular loop of 5 mm radius is placed 1 m away from a 60-Hz power line. The voltage induced on this loop is measured at
0.6 µV. What is the current on the power line
1 answer:
Answer:
i = 101.4A
Explanation:
The steps to the solution can be found in the attachment below.
We have been given the frequency f = 60Hz. From this we can calculate the angular frequency of the power line.
It is assumed that sinwt = –1 in order to calculate the time varying current. Although the magnitude of the current is large, consideration should also be given to the distance between the coil and the power line. The induced emf is small considering the area of the coil which is 7.85×10-⁵m².
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Answer:
Wavelength,
Explanation:
It is given that,
Speed of radio waves is
Frequency of radio waves is f = 101,700,000 Hz
We need to find the wavelength of WFNX’s radio waves. The relation between wavelength, frequency and speed of a wave is given by :
is wavelength
So, the wavelength of WFNX’s radio waves is 2.94 m.