A small circular loop of 5 mm radius is placed 1 m away from a 60-Hz power line. The voltage induced on this loop is measured at
0.6 µV. What is the current on the power line
1 answer:
Answer:
i = 101.4A
Explanation:
The steps to the solution can be found in the attachment below.
We have been given the frequency f = 60Hz. From this we can calculate the angular frequency of the power line.
It is assumed that sinwt = –1 in order to calculate the time varying current. Although the magnitude of the current is large, consideration should also be given to the distance between the coil and the power line. The induced emf is small considering the area of the coil which is 7.85×10-⁵m².
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To solve this problem it is necessary to apply the concepts related to the magnetic field.
According to the information, the magnetic field INSIDE the plates is,
Where,
Permeability constant
Electromotive force
r = Radius
From this deduction we can verify that the distance is proportional to the field
Then the distance relationship would be given by
On the outside, however, it is defined by
Here the magnetic field is inversely proportional to the distance, that is
Then,
Answer:
The pressure is 2.167 psi.
Explanation:
Given that,
Diameter = 1.5 feet
Height = 10 feet
We need to calculate the psi at 5 feet
Using formula of pressure at a depth in a fluid
Suppose the fluid is water.
Then, the pressure is
Where, P = pressure
= density
h = height
Put the value into the formula
Pressure in psi is
Hence, The pressure is 2.167 psi.