Answer:
.926 moles
Explanation:
Rounding :
H2 0 = 18 gm/mole
50 gm would then be 50 / 18 = 2.7777 moles of water
every two moles of 2 C6H6 produces 6 moles of water
2.7777/6 * 2 = .926 moles
Answer:
B. Anions are formed when an atom loses electrons.
Answer: Isotopes are useful in particular scientific fields. Theoretical astrophysicists point out that several new particles lead to new knowledge.
Explanation:
- When science reached the fact that chemical elements exist as a set of many different isotopes, it was the cornerstone in discovering the composition of atoms, but also the formation of modern knowledge about the understanding of chemical elements. The practical significance of the discovery above has importance in physics and physical and analytical chemistry. Also, thanks to isotopes, some diagnostic methods have been developed in specific sciences such as geology and archeology. By determining certain radioactive isotopes by means using these two sciences, it is possible to decide on the age of the individual samples.
- Theoretical physics is a viral branch of science today. This is a relatively young scientific discipline, and one of the greatest minds in the history of Stephen Hawking belonged to this discipline. The development and study of the atomic structure are significant for this scientific discipline. Some scientists point out that a large number of particles will be experimentally discovered in the future, as the atom has been found. It will undoubtedly cause new knowledge and reach for humanity. Thus, throughout history, the development of experimental physics has revealed a large number of particles that, in addition to protons, neutrons, and electrons, are contained in atoms.
This is a reduction half-reaction. Initially, gold exists as
, and after the reaction, it has been converted to elemental gold. To make this possible, three electrons must be added to <span>
. This fits within the definition of reduction reactions, where the reactant gains electrons in the reaction.</span>
<span> POCl3 is the correct way to write the chemical formula for this compound</span>
