Answer:
Therefore,
a)
b) I₂ = 2.55 Ampere
c) Power = 30.6 Watts
d) R₁ = 470.58 ohms.
Explanation:
Given:
Let the primary voltage be,
Secondary Voltage,
Secondary Resistance,
To Find:
a)
b) I₂ = ?
c) Power = ?
d) R₁ = ?
Solution:
The ratio of primary to secondary turns of the transformer, is the ratio of primary to secondary Voltage and is given by,
Substituting the values we get
For, rms current for the secondary supply,
Substituting the values we get
Now for average power at load,
Substituting the values we get
Now for resistance connected directly across the source line Power will remain same,
Substituting the values we get
Therefore,
a)
b) I₂ = 2.55 Ampere
c) Power = 30.6 Watts
d) R₁ = 470.58 ohms.
Answer:
No acceleration. All of the forces are acting equally on the paper air plane therfore It isn't going to move any where.
Yep. 'a', 'b', and 'c' are all accurate.
Actually, 'b' doesn't go far enough. Light is not only "faster than
anything else we know of", we now know that it's impossible for
anything with mass to ever hit that speed, so we can just quit looking.
<h2>
Answer: Toward the center of the circle.</h2>
This situation is characteristic of the uniform circular motion , in which the movement of a body describes a circumference of a given radius with constant speed.
However, in this movement the velocity has a constant magnitude, but its direction varies continuously.
Let's say is the velocity vector, whose direction is perpendicular to the radius of the trajectory, therefore
the acceleration is directed toward the center of the circumference.
Answer:
One should draw a diagram showing the placement of the charges.
When both charges of -Q are placed there will be no force in the vertical direction because of cancellation of forces.
A line from one corner of the square to the other makes an angle of 45 degrees,
2 cos 45 deg will be the force due to one charge.
2 * .707 = 1.41 N
So for both charges the force is (horizontal, vertical is zero)
2 * 1.41 = 2.82 N
b) is correct