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3 years ago

Why do all planets rotate around the sun in the ssame direction

1 answer:

Nutka1998 [239]3 years ago

3 0

This is because of the conservation of angular momentum, which allows most planets to spin in the same direction, but Venus and Uranus have seem to ignore this as they spin in different directions, as Venus spins clockwise and Uranus is on its side

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Explain why isokinetic exercises cannot generally be performed by individuals at home.

Lina20 [59]

Iso-kinetic exercises cannot be performed at home by an individual because they require specific machines that enable to exercise at a constant speed with professional guidance.

Explanation :

Iso-kinetic exercises are that kind of training regimes that require a constant pace to strengthen your muscles with the help of machines with significant specifications.

The machines involved in iso-kinetic exercises control your pace with variable resistance throughout the session and hence, it’s not a cup of tea for an individual to trace his/her performances and the respective improvements.

So, before going for a iso-kinetic schedule, be sure to have a word with your physiotherapist to train well with the machines under the specifications that can better suit your body and its requirements.

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3 years ago

Read 2 more answers

Properties can be observed only when the substance in a sample of matter are changing into different substance

Zolol [24]

The complete statement is "chemical properties can be observed only when the substance in a sample of matter are changing into different substance".

It states a key concept in chemistry.

A chemical property is the ability of a substance, element or compound, to transform into other substances either by decomposing or by combining with one or more substances.

This transformation is defined as chemical reaction.

During chemical reactions some chemical bonds are broken and others are formed leading to the formation of one or more different substances called products.

Some examples of chemical properties are: reactivity with oxygen, reactivity with water, acidity, basicity, oxidation, reduction. The only way to tell if a substance has certain chemical property is by letting it react and so observe the change of the original substance into one or more different substances.

8 0

3 years ago

What is the difference between mass and weight?

I am Lyosha [343]

Mass is the actual amount of material contained in a body and is measured by kg, gm, etc. Whereas weight is the force extorted by the gravity on that object mg. Note that mass is independent of everything but weight is different on earth, moon, etc.

5 0

3 years ago

A bug is moving along a meter stick in the negative direction at a constant speed of 0.85cm/s. After 42 seconds have passed the

Agata [3.3K]

Given that,

bug speed, v= 0.85 m/s

time, t =42 s

Final position of bug on meter stick was 27 cm

Starting position of bug on meter stick = ?

Since we know that,

s = vt

s= 0.85*42 = 35.7 cm

this is the distance covered by bug in the given time and velocity.

since the bug is moving in negative direction, starting point will be:

27.0 cm+ 35.7 cm = 62.7 cm

The bugs starting position on meter stick was 62.7 cm.

3 0

3 years ago

In a women's 100-m race, accelerating uniformly, Laura takes 1.82 s and Healan 3.07 s to attain

Sav [38]

Answer:

Laura is ahead and for a distance of 3.22 m

Explanation:

To solve this problem of one-dimensional kinematics, we have to find the acceleration and the final speed of each runner. Let's start with Laura

Lura data is acceleration time 1.82s, total run time 10.4 s and total distance 100m. In all the races the rest starts, so the initial speed is zero (Vo = 0)

Vf1= Vo + a1 t1

Vf1 = x/t

XT = X1 + X2

X1 = Vo t1 + ½ a1 t1²

X1 = ½ a1 t1²

X2 = Vf1 (t-t1)

This is the remaining time of the race after the acceleration is over.

XT = ½ a1 t1² + Vf1 (t-t1)

We remplace the expression of Vf1

XT = ½ a1 t1² + a1 t1 (t-t1)

Laura's aceleration (a1) is

a1= XT / [ ½ t1² + t1 (t-t1)]

a1= 100/ [ ½ 1.82²+ 1.82 (10.4 -1.82)]

a1= 5.79m/s2

We repeat the same calculation for the other Healan runner, whose data are: total distance 100m, acceleration time 3.07 s and total time 10.4 s

Vf2= Vo + a2 t2

Vf2 = x/t

XT = X3 + X4

X3 = Vo t2 + ½ a2 t2²

X3 = ½ a2 t2²

X4 = Vf2 (t-t2)

XT = ½ a2 t2² + Vf2 (t- t2)

XT = ½ a2 t2² + a2 t2 (t-t2)

The aceleration of Healan (a2)

a2 = XT / [½ t2² + t2 (t-t2)]

a2 = 100 / [½ 3,07²+ 3.07 (10.4 -3.07)]

a2 = 3.67 m / s2

We also need the final speeds of each runner

Laura Vf1 = Vo + a1 t1

Vf1 = 0 + 5.79 1.82

Vf1 = 10.54 m / s

Healan Vf2 = Vo + a2 t2

Vf2 = 0 + 3.67 3.07

Vf2 = 11.27 m / s

Having the acceleration and speed of each runner, you can start answering the questions

a) For t3 = 6.15s

Laura

The time to stop with constant speed is what remains after accelerating

XL= ½ a1 t1² + Vf1 (t3-t1)

XL= ½ 5.79 1.82² + 10.54 (6.15 – 1.82)

XL= 55.23 m

Healan

XH= ½ a2 t2² + Vf2 (t3-t2)

XH= ½ 3.67 3.07² + 11.27 (6.15-3.07)

XH= 52.01 m

(XL -XH)= 55.23- 52.01

(XH -XL)= 3.22 m

It is appreciated from these results that Laura is ahead and for a distance of 3.22 m

b) If we analyze the acceleration values of each runner, knowing that they leave the rest and that Healan at the end has a speed greater than Laura, the point of maximum distance difference is when Laura stops accelerating t = 1.82 s

XL= ½ a1 t12

XL= ½ 5.79 1.822

XL= 9.59 m

XH = ½ a2 t12

XH= ½ 3.67 1.822

XH= 6.08 m

The maximum distance difference is 3.51 m

c) Already analyzed in the previous part 1.82 s, since the Laura stop accelerating and Heala continue with acceleration will travel greater distances in equal time units

6 0

3 years ago