All categories

3 years ago

How a measuring scale measure our weight

1 answer:

5 0

Scales measure how much something weighs—and they do it by measuring how much force exists between the object you're weighing and planet Earth. Although scales measure force, they give you measurements of mass in kilograms, grams, pounds, or whatever.

You might be interested in

An airplane is flying 340 km/hr at 12o east of north. the wind is blowing 40 km/hr at 34o south of east. what is the plane's act

seropon [69]

Define an x-y coordinate system such that
The positive x-axis = the eastern direction, with unit vector $\hat{i}$ .
The positive y-axis = the northern direction, with unit vector $\hat{j}$ .

The airplane flies at 340 km/h at 12° east of north. Its velocity vector is
$\vec{v}_{1} = 340(sin(15^{o})\hat{i} + cos(15^{o})\hat{j} ) = 88\hat{i} + 328.4\hat{j}$

The wind blows at 40 km/h in the direction 34° south of east. Its velocity vector is
$\vec{v}_{2} =40(cos(34^{o})\hat{i} - sin(24^{o})]\hat{j}) = 33.1615\hat{i} -22.3677\hat{j})$

The plane's actual velocity is the vector sum of the two velocities. It is
$\vec{v}=\vec{v}_{1}+\vec{v}_{2} = 121.1615\hat{i}+306.0473\hat{j}$

The magnitude of the actual velocity is
v = √(121.1615² + 306.0473²) = 329.158 km/h

The angle that the velocity makes north of east is
tan⁻¹ (306.04733/121.1615) = 21.6°

Answer:
The actual velocity is 329.2 km/h at 21.6° north of east.

8 0

3 years ago

Show that atmosphere exerts pressure.

Maru [420]

Because gas particles in the air like particles of all fluids are constantly moving and bumping into things, they exert pressure. The pressure exerted by the air in the atmosphere is greater close to Earth's surface and decreases as you go higher above the surface.

<u>Explanation</u>:

Fill roughly one-third of a cup with water. Then, cover the mouth of the cup completely with a flat, hard cardboard. Using your hand to keep it in place, turn the cup upside down. When you remove your hand, the the cardboard stays in place.

One would expect that due to gravity, the water will fall, and even the cardboard will. However, it does not, which means that something must be applying an upward force on the cardboard. This is nothing other than air pressure, which applies a force across the surface of the cardboard in an upward direction.

Thus we can demonstrate that air exerts pressure, because otherwise, the water would have fallen.

3 0

3 years ago

16. How much force would it take to accelerate a 75kg object by 5 m/szą

patriot [66]

Answer:

The force experienced is 375 N.

Explanation:

Here,

Mass of the object( M)= 75 kg

Acceleration of the body(a) =5 m/s²

Force required to accelerate the body( F) =?

Then, we know ,

From newton's second law of motion,

$F=M*a$

= $75* 5$

=375 kgm/s²

= 375 Newton

So, The force experienced by the 75 kg body that undergoes an acceleration of 5 m/s² is 375 N.

7 0

3 years ago

How large must the coeffficient of static friction be between the tires and the road if a car is to round a level curve of radiu

m_a_m_a [10]

Answer:

Coefficient of static friction required = 0.94

Explanation:

Coefficient of static friction required $=\frac{v^2}{gR}$

Velocity, v = 120 km/h = 33.33 m/s

g = 9.81 m/s²

R = 120 m

Coefficient of static friction required $=\frac{33.33^2}{9.81\times 120}=0.94$

Coefficient of static friction required = 0.94

5 0

3 years ago

Liquid water is nearly 1,000 times denser than air. Thus, for every 32.0 feet (9.75 m) a scuba diver descends below the water's

Sergio [31]

Answer:

ΔV = -2.1 L

Explanation:

To solve this exercise we can use the ideal gas equation for two points

PV = nRT

P₁V₁ = P₂ V₂

where point 1 is on the surface and point 2 is at the desired depth,

V₂ = $\frac{P_1}{P_2} \ V_1$

let's calculate

V₂ = ( $\frac{1 atm}{2.5 atm}$ ) 3.5 L

V₂ = 1.4 L

this is the new volume, the change in volume is

ΔV = V₂ -V₁

ΔV = 1.4-3.5

ΔV = -2.1 L

4 0

3 years ago