Explanation:
According to Thermal Expansion of solids:
A particle moves along a circular path over a horizontal xy coordinate system, at constant speed. At time t1 = 4.50 s, it is at
point (5.80 m, 5.60 m) with velocity (3.50 m/s) j and acceleration in the positive x direction. At time t2 = 11.7 s, it has velocity (–3.50 m/s) i and acceleration in the positive y direction. What are the (a) x and (b) y coordinates of the center of the circular path? Assume at both times that the particle is on the same orbit.
1 answer:
Answer:
a) x=11.15m
b) y= 5.6m
Explanation:
This is the given data:
t1=4.5s t2=11.7s
V1=3.5 (j)m/s V2=-3.5 (i)m/s
a1 = a(i) a2 = a(j)
r1 = 5.8(i)+5.6(j) m
From this data we conclude that the orbit is as the one shown in the picture.
So, the position of the center will be rc = r1 + R(i) = (5.8+R)(i) + 5.6(j)
Calculating the distance traveled by the particle:
S = V*Δt = 3.5 * (11.7-4.5) = 25.2m
Since S = θ * R and from the picture we know that θ = 3π/2
R = 5.35m
Now we calculate the center of the orbit as:
rc = r1 + R(i) = (5.8+5.35)(i) + 5.6(j) = [11.15(i) + 5.6(j)] m
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a) Average velocity for her run north: 2.68 m/s north
b) The average velocity for the whole trip is zero
c) The average speed for the whole trip is 1.95 m/s
Explanation:
a)
In this part of the problem we only want to consider the part when Micha is running north.
The average velocity is given by:
where
d is the displacement (a vector connecting the initial position to the final position of motion)
t is the time
For the part running north, we have
north is the displacement
is the time interval
Substituting,
north (we have to specify also the direction, since velocity is a vector)
b)
As we said, average velocity is given by
where
d is the displacement
t is the time
If we consider the whole trip, however, the displacement is zero:
d = 0
Because Micha returns home, so the initial position corresponds to the final position of motion. Therefore, the average velocity is also zero:
v = 0
c)
The average speed is given by
where
d is the distance covered (the total length of the path, regardless of the direction)
t is the time interval
Since MIcha ran 2 miles north and then 2 miles back, the total distance is
And the time taken is
So, the average speed is
And since speed is a scalar, there is no need to specify a direction.
Learn more about speed and velocity:
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Answer:
the static charge is not always distributed on the surface of the conductor, there are also charges in the volume but of lesser magnitude
Explanation:
In this hypothetical system the electric force is of type
F =
in this case the force decays to zero much faster,
if we call Fo the force of Coulomb's law
F₀ =
assuming the constant k is the same
the relationship between the two forces is
F / F₀ = 1 / r
F = F₀ / r
when analyzing this expression the force decays much faster to zero.
In an electric conductor, charges of the same sign may not feel any repulsive force from other charges that are at a medium distance, so there is a probability that some charges are distributed in the volume of the material, this does not happen with coulomb's law
Consequently, the static charge is not always distributed on the surface of the conductor, there are also charges in the volume but of lesser magnitude