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3 years ago

Can someone help me pls

Chemistry

2 answers:

BartSMP [9]3 years ago

7 0

I can help. What is wrong.

Salsk061 [2.6K]3 years ago

5 0

Answer:

Helium (He)

Explanation:

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If Magnesium Sulfide reacts with oxygen in the air, what will be produced?

sweet [91]

IF magnesium sulfide reacts with oxygen in the air it will produce

magnesium oxide + sulfur (IV) oxide

<u><em>explanation</em></u>

magnesium sulfide burn in oxygen to produce magnesium oxide and sulfur (iv) oxide according to the equation below

2MgS +3O2 →2MgO +2SO2

that is 2 moles of MgS react with 3 moles of O2 to produce 2 moles of MgO and 2 moles of SO2

6 0

3 years ago

A latex balloon at sea level and room temperature (25°C) has a volume of 2.42 L. When the balloon is released by the child holdi

yarga [219]

Answer:

The answer to your question is: V2 = 1.94 l

Explanation:

Data

V1 = 2.42 l

T1 = 25°C

P1 = 1 atm

V2 = ?

T2 = 25 -11 = 14°C

P2 = 1(0.7) = 0.7 atm

Formula

P1V1/T1 = P2V2/T2

Clear V2 from the equation

V2 = P1V1T2/ P2T1

V2 = (1)((2.42)(14) / (0.7)(25)

V2 = 33.88 / 17.5

V2 = 1.94 l

6 0

3 years ago

True or False: Your blood is a neutral solution.

MaRussiya [10]

Answer:

True

Explanation:

Neutral solutions maintain a pH of 7. Water and human blood are great examples of neutral solutions. Acids mixed with bases can be neutralized and given a pH of 7.

8 0

3 years ago

In a chemical reaction, 28g of iron reacts with 16g of sulfur to produce _________ of iron sulfide.

kirill115 [55]

Hello!

In a chemical reaction, 28g of iron reacts with 16g of sulfur to produce _________ of iron sulfide.

We have the following data:

m(Fe) - mass of iron = 28 g

m(S) - mass of sufur = 16 g

MM(Fe) - molar mass of iron ≈ 56 g/mol

MM(S) - molar mass of sulfur ≈ 32 g/mol

n(Fe) - number of mol of iron = ?

n(S) - number of mol of sulfur = ?

Solving:

* to n(Fe)

$n_{Fe} = \dfrac{m_{Fe}}{MM_{Fe}}$

$n_{Fe} = \dfrac{28\:\diagup\!\!\!\!\!g}{56\:\diagup\!\!\!\!\!g/mol}$

$\boxed{n_{Fe} = 0.5\:mol}$

* to n(S)

$n_{S} = \dfrac{m_{S}}{MM_{S}}$

$n_{S} = \dfrac{16\:\diagup\!\!\!\!\!g}{32\:\diagup\!\!\!\!\!g/mol}$

$\boxed{n_{S} = 0.5\:mol}$

The stoichiometric reaction will be in the same proportion (1 : 1), let us see:

$Fe + S \Longrightarrow FeS$

1 mol of Fe -------------- 1 mol of FeS

0.5 mol of Fe ------------ 0.5 mol of FeS

Will the reaction of the iron mass with the mass of sulfur produce how many grams of iron sulfide? We will see:

n(FeS) - number of mol of iron sulfide = 0.5 mol

m(FeS) - mass of iron sulfide = ? (in grams)

MM(FeS) - Molar Mass of iron sulfide = 56 + 32 = 88 g/mol

Solving:

$n_{FeS} = \dfrac{m_{FeS}}{MM_{FeS}}$

$m_{FeS} = n_{FeS}*MM_{FeS}$

$m_{FeS} = 0.5\:mol\!\!\!\!\!\!\!\!\!\!\!\dfrac{\hspace{0.6cm}}{~}*88\:\dfrac{g}{mol\!\!\!\!\!\!\!\!\!\!\!\dfrac{\hspace{0.6cm}}{~}}$

$\boxed{\boxed{m_{FeS} = 44\:g}}\:\:\:\:\:\:\bf\blue{\checkmark}\bf\green{\checkmark}\bf\red{\checkmark}$

Answer:

44 grams of iron sulfide

___________________________

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3 years ago

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Doing the same final thanks

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4 years ago

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