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34kurt
3 years ago
13

Why do we experience the changing of the seasons on earth

Chemistry
1 answer:
iren2701 [21]3 years ago
4 0

<u>Answer:</u>

Earth's axis and position around the sun.

<u>Explanation:</u>

Earth's tilted axis causes the seasons to change. Throughout the year, different parts of Earth acquire the Sun's most direct rays(Or heat) because of the orbital rotation of Earth. So, when the North Pole tilts toward the Sun, it's summer inside the Northern Hemisphere. And whilst the South Pole tilts towards the Sun, it is winter within the Northern Hemisphere and vise versa.

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Based on the equation below , how many moles of carbon monoxide (CO) are needed to react completely with 1.75 moles of iron (lll
blagie [28]
From the equation:
1 mole Fe₂O₃ needs 3 moles of CO
1.75 moles require:
1.75 x 3
= 5.25 moles of CO
3 0
3 years ago
An ion with an atomic number of 34 and 36 electrons has a __________ charge
Solnce55 [7]
<span>negative charge. The atomic number of 34 tells you immediately that the ion has 34 protons. Since it also has 36 electrons, it has 2 more electrons than needed to be neutral. So the ion will have a negative charge since electrons have a negative charge.</span>
5 0
3 years ago
When 35.0 mL of 0.400 M hydrobromic acid and 35.0 mL of 0.400 M ammonia are combined, the pH of the resulting solution will be :
Kay [80]

Answer:

B. Equal to 7.

Explanation:

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As the initial pH of water is 7,0 the addition of 35.0mL of 0.400M HBr will produce a pH less than 7,0. But, the same effect of decreasing pH is reverted for the addition of 35.0mL of 0.400M HNO3.

That means the net effect of the two addition is to have a pH:

B. Equal to 7.

I hope it helps!

3 0
3 years ago
Mg(s) + ½O2(g) → MgO(s) + 146 kcal/mole H2(g) + ½O2(g) → H2O(g), ΔH = -57.82 kcal/mole What type of reaction is represented by t
professor190 [17]
Answer is: both reactions are exothermic.
<span>
In exothermic reactions, heat is released and enthalpy of reaction is less than zero (as it show second chemical reaction).
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4 0
3 years ago
Radium has a half-life of 1,620 years. In how many years will a 1 kg sample of radium decay and reduce to 0.125 kg of radium?
Tasya [4]
We can calculate years by using the half-life equation. It is expressed as:

A = Ao e^-kt

<span>where A is the amount left at t years, Ao is the initial concentration, and k is a constant.

</span>From the half-life data, we can calculate for k.

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<span>k = 4.28 x 10^-4
</span>
0.125 = 1 e^-<span>4.28 x 10^-4 (</span>t)
t = 4259 years
7 0
3 years ago
Read 2 more answers
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