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vlada-n [284]
3 years ago
7

What elements are found in potassium oxide

Chemistry
2 answers:
andreyandreev [35.5K]3 years ago
6 0
Potassium and <span>oxygen and patassion oxide is an ionic compound hope this helps and plz rate below and thank me on my profile plz and thnx</span>
GaryK [48]3 years ago
3 0
Elements that are found in potassium oxide is oxygen.
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inspiration means

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Reacting Solutions of Aluminum Chloride with Potassium Hydroxide
gizmo_the_mogwai [7]

1Al2(SO4)3 + 3ZnCl2 → 2AlCl3 + 3ZnSO4

The coefficients represents moles. There is 1 mole of Aluminum Sulfate, 3 moles of Zinc(II) Chloride, 2 moles of Aluminum Chloride, and 3 moles of Zinc(II) Sulfate.

Now add all the coefficients/moles.

9 is the sum of all the coefficients.

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Write balanced equations for all the reactions in the catabolism of glucose to two molecules of glyceraldehyde 3-phosphate (the
Reil [10]

Solution :

The balanced chemical equation are

The Catabolism of the glucose takes place in five stages :

1. Glucose + $ATP$ → glucose - $6$ - phosphate $+ ADP$  ,  $\Delta G^0=-16.7 \ kJ/mol$

2. Glucose - $6$ - phosphate → Fructose - $6$ - phosphate ,  $\Delta G^0=1.7 \ kJ/mol$

3. Glucose - $6$ - phosphate + $ATP$ → $ADP$ + Fructose - $1,6- \text{biophosphate}$,  $\Delta G^0=-14.2 \ kJ/mol$

4. Fructose - $1,6- \text{biophosphate}$  → dihydroxyacetonephosphate + glyceraldehyde  $-3 - $ phosphate,   $\Delta G^0=23.8 \ kJ/mol$

5. Dihydroxyacetonephosphate → glyceraldehyde  $-3 - $ phosphate , $\Delta G^0=7.5 \ kJ/mol$

Therefore, the overall net equations

Glucose + $2ATP \rightarrow$ glyceraldehyde  $-3 - $ phosphate + $2ADP$ $\Delta G^0=2.1 \ kJ/mol$

5 0
3 years ago
Gallium arsenide, GaAs, has gained widespread use in semiconductor devices that convert light and electrical signals in fiber-op
stira [4]

Answer:

Five peaks  

Explanation:

GaAs would show two peaks:

Ga-69 + As-75 = 144

Ga-71 + As-75 = 146

Their intensities are in the ratio 60 : 40 = 100:67.

Ga₂S₂ would show three peaks:

Ga-69 + Ga-69 + 2As-75 = (Ga-69)₂(As-75)₂ = 288

Ga-69 + Ga-71 + 2As-75 = (Ga-69)(Ga-71(As-75)₂ = 290

Ga-71 + Ga-71 + 2As-75 = (Ga-71)₂(As-75)₂ = 292

Their relative intensities are in the ratio

(60 + 40)² = 60² : 2×60×40 : 40² = 3600 : 4800 : 1600 = 75 : 100 : 33

A spectrum of a mixture of GaAs and Ga₂As₂ would show five peaks:

Two at m/e 144 and 146 with intensity ratios 100: 67 and

Three at m/e 288, 290, and 292 with intensity ratios 75:100 :33.

We cannot predict the absolute sizes of the peaks because we do not know the relative amounts of GaAs and GaAs₂.

6 0
4 years ago
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