Answer:
dry
Explanation:
it will dry the hydrogen chloride to the ammonia
Answer:
18 DAYS IS THE HALF LIFE OF THE RADIOISOTOPE.
Explanation:
Using the formula
Nt = No * (1/2)^t/t1/2
where;
Nt = amount remaining = 25 g
No = Initial amounrt of the radioisotope = 50 g
t = time elapsed = 18 days
t1/2 = half life = unknown
Substitute the values into the equation and obtain the half life of the radioisotope;
Nt = No * (1/2) ^t/t1/2
25 = 50 * (1/2) ^18/t1/2
25 /50 = (1/2)^18/ t1/2
1/2 = (1/2)^18/t1/2
1/2)^1 = (1/2)^18/t1/2
1 = 18/t1/2
t1/2 = 18 days.
So therefore the half life of the radioisotope is 18 days.
<span>Water can resist a greater external force than ethanol due to its greater surface tension.
Reason:
Surface Tension in liquids is caused by the cohesive forces among the molecules of liquids at the surface. Means the liquids molecules at the surface have a net attractive interactions with molecules beneath them and cause them to contract causing tension.
Now comparing water and ethanol, water has stronger intermolecular interactions than ethanol because water has two Hydrogen bongd donors (i.e. Hydrogens directly attached to oxygen atom) while ethanol has only one Hydrogen Bond Donors. This strong intermolecular interactions in water makes greater surface tension.</span>
It’s an example of substitution
Answer:
Increasing the temperature will result in increase in number of moles of CO_{2}
Explanation:
Concentration of pure solids and liquids remain constant throughout a reaction. Hence their concentrations terms are not involved in expression for equilibrium constant. Hence removing or adding solid
will not affect change in number moles of
.
In the forward direction, pressure increases due to formation of gaseous CO_{2}. Hence, according to Le-chatelier's principle, increase in pressure will result formation of more reactant.
As it is an endothermic reaction therefore heat is consumed in formation of CO_{2}. So, according to Le-chatelier;s principle, increasing the temperature will result in increase in number of moles of CO_{2}.
Correct option (D)