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Gwar [14]
3 years ago
6

An astronaut throws a rock. the rock travels through outer space at a constant velocity. which statement applies to the motion o

f this rock?
A- an unbalanced force is acting on the rock, causing it to accelerate.
B-the rock will undergo constant acceleration until a force acts on it.
C- The rock will continue on its current path until an unbalanced force acts on it.
D- The force that makes the rock move through space is equal to its mass divided by its velocity
Physics
2 answers:
frez [133]3 years ago
7 0

This is an example of Newton's first law of motion:


An object at rest will remain at rest unless an unbalanced force acts upon it. Similarly, a moving object will remain moving in a straight line at constant velocity unless an unbalanced force acts upon it.


The answer is C.

Anika [276]3 years ago
5 0

Answer:

B.  a force equal to zero

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A thin walled spherical shell is rolling on a surface. What
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Answer:

=\frac{1/3}{5/6} = 0.4

Explanation:

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we know linear speed is given as v = r\omega

translational K.E = \frac{1}{2} mv^2 = \frac{1}{2} m(r\omega)^2

rotational K.E = \frac{1}{2} I \omega^2 = \frac{1}{2} \frac{2}{3} MR^2 \omega^2

total kinetic energy will be

K.E = \frac{1}{2} m(r\omega)^2 + \frac{1}{2} \frac{2}{3} MR^2 \omega^2

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fraction of rotaional to total K.E

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8 0
3 years ago
A 20.0-N weight slides down a rough inclined plane which makes an angle of 30 degree with the horizontal. The weight starts from
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Answer:

1270.64\ \text{J}

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mg = Weight of object = 20 N

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u = Initial velocity = 0

d = Distance moved by the object = 150 m

\theta = Angle of slope = 30^{\circ}

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The force balance of the system is

\dfrac{1}{2}m(v^2-u^2)=(mg\sin\theta-f)d\\\Rightarrow \dfrac{1}{2}mv^2=mg\sin\theta d-fd\\\Rightarrow fd=mg\sin\theta d-\dfrac{1}{2}mv^2\\\Rightarrow fd=20\times \sin 30^{\circ}\times 150-\dfrac{1}{2}\times \dfrac{20}{9.81}\times 15^2\\\Rightarrow fd=1270.64\ \text{J}

The work done against friction is 1270.64\ \text{J}.

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3 years ago
What is the definition of visible white light wave (RoyGBive)
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There's no such thing as a wave of white light.  Every light wave with
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Because so little can be found of the first rocks to form on
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B is the answer

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0-/-<

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