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11 months ago

The two forces to the right are friction which one would be the force of kinetic friction?

Physics

1 answer:

xeze [42]11 months ago

8 0

Answer:

40 N

Explanation:

Both forces to the right are friction forces. The 40 N force has to be the kinetic friction force because kinetic friction is always less than static friction. So, the 80 N force has to be the static friction force, which is always greater than the kinetic friction.

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three different-mass projectiles are launched at different angles of elevation from the top of a building. each particle has the

MrRa [10]

The correct option is b. The one with the lowest mass.

An object's kinetic energy is determined by

k=1/2mv^2

where

m is the object's mass.

v is the object's speed.

The three missiles in this puzzle have varying masses but the same beginning kinetic energy.

The three projectiles will all have the same kinetic energy when they hit the ground because mechanical energy is conserved, assuming there is no air resistance (because the potential energy that they have lost is the same, since they have been launched from the same height, and they reach the same final altitude, the ground).

hence,

K1=k2=k3

To know more about kinetic energy refer to brainly.com/question/14604194

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iren2701 [21]

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Vitek1552 [10]

Answer:

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Explanation:

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2 years ago

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mario62 [17]

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do your mom hard to get out of the house you doing today no classes are you doing today no classes are you doing today no classes are not sleeping in my bed you have any best to get the meaning do you want for it is my friend I will be there at 12 I have send me a even if we don't ask everyone e for it was a screenshot I am excited everything except you eat your eyes everything except everything else ever even know if everyone e and 10 even though it was kiss emoji everything else ever eyebrows yet I eat early to get enough everything except everything is your class finish up early enough even know what is going on with out hajab I have send it out to edit a video on e a video on each e

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