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Answer:
<em>Rt = 8 ohm</em>
<em>I = 2 A</em>
<em>Vab = 12 V</em>
<em>VbΓ = 4 V</em>
<em>VaΓ = 16 V</em>
Explanation:
<u>Electric Circuits</u>
We'll apply Ohm's formula to solve the circuit shown on the image:
V = R.I
Where V is the voltage, R is the resistance, and I is the current.
The circuit has two resistances connected in series, thus the total resistance is:
Rt = R1 + R2 = 6 ohm + 2 ohm = 8 ohm
Now the current is:
I = 2 A
The voltages are calculated below:
Vab = R1 * I = 6 ohm * 2 A = 12 V
VbΓ = R2 * I = 2 ohm * 2 A = 4 V
VaΓ = Vab + VbΓ = 12 V + 4 V = 16 V
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Answer:</h2>
<h3>Scientific Notation was developed in order to easily represent numbers that are either very large or very small. ... As you can see, it could get tedious writing out those numbers repeatedly. So, a system was developed to help represent these numbers in a way that was easy to read and understand: Scientific Notation.</h3>
The question is incomplete. The complete question is:
A 500-turn coil with a 0.250 m2 area is spun in the Earth’s 5.00 × 10−5 T field, producing a 12.0 kV maximum emf. (a) At what angular velocity must the coil be spun? (b) What is unreasonable about this result? (c) Which assumption or premise is responsible?
Answer:
ω=1.92 × 106 rad/s
Explanation:
Emfo= 12.0×10^3 V
N= 500 turns
A= 0.250 m^2
B= 5.00×10^-5
ω=??????
From
Emfo= NABω
ω= Emfo/NAB
ω= 12.0×10^3/500×0.250×5.00×10^-5
ω=1.92 × 106 rad/s
b) This angular velocity is unreasonably high, it is very much higher than a value that can be obtained for any mechanical system.
c) The unreasonable assumption or premise that a peak voltage as high as 12.0kV may be obtained.
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